A cylinder fed by a membrane reservoir
Take a cylinder of radius and length , leaving out its end connections. Choose the pulling direction and force positive along the axis. Principal curvatures are and zero. Set spontaneous curvature and pressure difference to zero. A sufficiently large reservoir supplies membrane at specified tension .
The tube area is . Multiply the bending energy density by this area and add the tension cost of taking area from the reservoir. This fixed-tension condition differs from the fixed-total-area condition in the shape experiment.
Source: I. Derényi · W. Helfrich
Minimize radius, then differentiate length
At fixed length, differentiate with respect to radius. The bending slope is negative and the tension slope positive. Setting their sum to zero gives the equilibrium radius. A positive second derivative confirms a minimum against radial changes.
Insert this radius into the energy per length. Total energy grows linearly with length, so is constant. The plateau describes an already formed, sufficiently long tube. Initial protrusion from a membrane has a different shape and end-region force.
Source: I. Derényi · W. Helfrich
Moving the instrument also stretches it
Connect the pulling probe to a linear spring of stiffness . Let be the axial reservoir-to-support distance and the effective tube length. The spring extension is . Static balance equates its force with the tube force.
On a long-tube plateau, spring extension stays fixed, so further support motion becomes tube length. A softer instrument needs a larger displacement to supply the same force. Stop using the cylindrical limit when the remaining tube approaches the scale of the end regions. The experiment begins with an existing long tube; pull stroke adds to the initial support coordinate. During motion, drag allows instantaneous spring force to differ from the plateau until the tube settles.
Worked example of force and displacement
Choose teaching parameters and . Then and . This radius is much smaller than a micrometer-scale vesicle, so apparatus drawings often magnify the tube diameter.
For and , spring displacement is approximately and tube length . Treating the support distance as tube length would overcount by the spring displacement.
Doubling tension narrows the tube and raises force. Doubling rigidity broadens it and also raises force. Observing both quantities helps distinguish the causes.
Recover two parameters from two measurements
Plateau force alone determines the product . Add an independent radius measurement: multiplying force by radius gives rigidity and dividing force by radius gives tension. Use a radius measured independently of the assumed rigidity for this second observable.