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FR20 · Bending and pulling

Pulling a Membrane Tether

Why does a long membrane tube resist pulling with nearly constant force? A long tube settles at the radius where bending and membrane tension balance. Adding another length then costs the same energy, so the static pulling force stays constant. Pulling at finite speed adds a drag force that relaxes when the trap stops.

Drag an optical trap to extend a preformed membrane tube. Watch the bead lag behind the trap, then let the pulling force settle as the tube grows.

Interactive modelPulling a Membrane Tether
Tube radius58.6 nm58.6\,\mathrm{nm}
Trap force8.83 pN8.83\,\mathrm{pN}
Tube length1.60 μm1.60\,\mathrm{\mu m}
Bead displacement147 nm147\,\mathrm{nm}

Pulling faster costs extra force

Cyan: simulated trap force. Dashed amber: static cylinder force. The force falls back when the trap stops. The marker follows the frame above.

Force in piconewtons over time in seconds
How the pulling record is calculated

An exact linear propagator advances the bead under a stationary trap, a constant-speed pull and a final hold. Export includes all times, positions, forces, units and model version. The bead drag is a chosen teaching parameter, not a calibration of a specific instrument.

Physics tutorial

A tube trades bending for area

BackgroundAn optical trap can hold a bead attached to a membrane tube. Moving the trap pulls membrane out of a much larger reservoir.

Why it mattersThe tube radius reveals a balance of bending and tension. The bead displacement measures the force needed to keep that tube growing.

Start with the essentials

Focus question
Why does a long membrane tube resist pulling with nearly constant force?
One-sentence intuition
Once a tube has a fixed radius, each extra length costs the same membrane energy.

Core mathematical model

Energy per tube length

E/L=πκ/r+2πσrE/L=\pi\kappa/r+2\pi\sigma r

The first term penalizes a narrow, strongly curved tube. The second charges tension for the membrane area added to it.

Radius and static pulling force

r0=κ/(2σ),f0=2π2κσr_0=\sqrt{\kappa/(2\sigma)},\qquad f_0=2\pi\sqrt{2\kappa\sigma}

Minimize the energy with respect to radius, then differentiate it with respect to length. These are the long-cylinder, zero-pressure results.

What the trap measures

F=ktrap(X−L),ζL˙=F−f0F=k_{\mathrm{trap}}(X-L),\qquad\zeta\dot L=F-f_0

Trap position and tube end position use the same axial origin; a constant bead-radius offset is suppressed in both. The specified drag turns excess trap force into tube motion.

Common difficulties

A plateau and a moving bead

Typical misconceptionThe optical force must always equal the static tube force.

Better mental modelDuring a finite-speed pull, the bead needs extra force to overcome drag. When the trap stops, the bead catches up and the force relaxes.

Run the experiment

  1. 01

    Watch the bead lag

    Watch A growing tube, then pause during the pull.

    What to observe: The amber trap centre sits ahead of the cyan bead. Their separation sets the force in the trace below.
  2. 02

    Change tension

    Choose Tension makes a thin tube.

    What to observe: The tube becomes thinner and its static pulling force rises.
  3. 03

    Move the trap yourself

    Drag the amber trap handle, then release it.

    What to observe: The bead follows with a delay, then settles at the displacement required by the static force.

Related experiments and articles

Membranes and vesicles · Reading path

From curvature to active membrane measurements

Articles on this path that use this experiment, followed by the other experiments they suggest.

  1. ArticleThe force needed to pull a membrane tube
  2. LabOptical Tweezers: Brownian CalibrationStudy an independent probe calibration
  3. ArticleReading from a tube formula to an active-membrane paper
  4. LabMeasuring a Flickering MembranePreserve a reproducible observation
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