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Sandbox Physics

M032 · Momentum / restitution

One-Dimensional Collision Bench

Release two carts on a frictionless rail. Compare elastic exchange, dissipation and a common final velocity; fit camera tracks before and after the contact trigger. A moving observer changes momentum and kinetic energy while leaving restitution and collision loss unchanged.

Interactive modelOne-Dimensional Collision Bench
Elapsed time0 s0\,\mathrm{s}
Horizontal momentum in camera frame0 kg m s−10\,\mathrm{kg\,m\,s^{-1}}
Kinetic energy in camera frame0 J0\,\mathrm{J}
Dissipated impact energy0 J0\,\mathrm{J}
Delivered normal impulse0 N s0\,\mathrm{N\,s}
Predicted contact timeNo event\text{No event}
Restitution from camera velocitiesCollecting\text{Collecting}
Camera position residual RMSCollecting\text{Collecting}
Momentum conservation defect0 kg m s−10\,\mathrm{kg\,m\,s^{-1}}
Kinetic plus heat balance defect0 J0\,\mathrm{J}
First velocity in camera frame0 m s−10\,\mathrm{m\,s^{-1}}
Second velocity in camera frame0 m s−10\,\mathrm{m\,s^{-1}}

Physics tutorial

A collision seen by two observers

BackgroundA cart collision transfers equal and opposite impulses. The total momentum is conserved in any inertial frame, while kinetic energy is conserved only for an elastic collision.

Why it mattersOpenStax University Physics, sections 9.4 and 9.5 provide the momentum and collision reference. This bench adds a calibrated contact trigger and a noisy camera so restitution must be measured from two fitted velocity segments.

Start with the essentials

Focus question
Can a moving camera change the energy loss or the restitution of the same impact?
One-sentence intuition
Fit the velocities first. Compare the two normal relative velocities; an observer boost cancels from their difference.

Core mathematical model

Momentum and impulse

m1u1+m2u2=m1v1+m2v2,m1(v1−u1)=−m2(v2−u2)m_1u_1+m_2u_2=m_1v_1+m_2v_2,\qquad m_1(v_1-u_1)=-m_2(v_2-u_2)

There is no external horizontal impulse during contact.

Restitution from two velocity fits

e=v2−v1u1−u2,u1>u2e=\frac{v_2-v_1}{u_1-u_2},\qquad u_1>u_2

Four frames on each side are the minimum. A poorly resolved closing velocity makes the ratio unreliable.

An independent loss identity

Kbefore−Kafter=12m1m2m1+m2(1−e2)(u1−u2)2K_{\mathrm{before}}-K_{\mathrm{after}}=\frac12\frac{m_1m_2}{m_1+m_2}(1-e^2)(u_1-u_2)^2

The energy ledger is recomputed from both final velocities, then compared with this reduced-mass reference.

Changing the observer

vi′=vi−U,P′=P−(m1+m2)U,K′=K−UP+12(m1+m2)U2v_i'=v_i-U,\quad P'=P-(m_1+m_2)U,\quad K'=K-UP+\frac12(m_1+m_2)U^2

The conserved momentum makes the boost terms cancel from the before–after kinetic energy difference.

Common difficulties

Momentum is not energy

Typical misconceptionConserved momentum means conserved kinetic energy.

Better mental modelUse the dissipative preset: momentum closes while kinetic energy becomes impact loss.

A common velocity is special

Typical misconceptionEvery dissipative collision makes the carts stick.

Better mental modelOnly zero restitution removes the relative normal velocity on this one-dimensional rail.

Sampling is an instrument limit

Typical misconceptionA known trajectory guarantees a camera estimate.

Better mental modelChoose too few pre-impact frames; the instrument refuses a fit even though the model predicts the impact.

Run the experiment

  1. 01

    Measure before comparing

    Record the default impact and compare the measured restitution with its setting.

    What to observe: Dots and fitted velocities are noisy; the analytic trajectory is the reference.
  2. 02

    Exchange or share velocity

    Compare equal-mass elastic and common-velocity presets.

    What to observe: Only the common-velocity case removes all rail-relative kinetic energy.
  3. 03

    Move the observer

    Change observer velocity and record again.

    What to observe: Momentum and kinetic energy change; impact loss and restitution agree.
  4. 04

    Break the instrument

    Try separating carts and too few pre-impact frames.

    What to observe: No impulse and insufficient sampling produce different failure states.