Define the angles before following the ray
Put the observer at the left, the lens plane a distance away, and the source plane a distance away. The lens-source separation is . These are positive lengths. In the nearby Galactic setting we use ordinary Euclidean distances, so the last distance is their difference. Cosmological lensing instead needs the appropriate angular-diameter distances.
Measure sky angles from the direction of the lens. The true source direction is ; an observed image direction is . On a line through the lens, rightward angles are positive. An image to the left has a negative angle even when the source is on the right.
The weak-field deflection of light passing a compact mass at impact distance is the following input from general relativity. Here is the gravitational constant and is the speed of light. The ray stays far outside the lens’s gravitational radius.
Reading: Bozza et al., VBMicroLensing, arXiv:2410.13660v1; A&A 694 A219 (2025)
Use the triangle to find the image
Trace the observed ray back from the telescope to the lens plane, then follow its deflected direction to the source plane. Similar triangles relate the displacement in the source plane to the deflection. The thin-lens approximation places the bending at one plane; the true gravitational field is spread out along the path.
Group the distances and mass into an angular scale, the Einstein radius . It is the radius of the image ring when source, compact lens and observer line up. This is an angle, despite the word radius.
Reading: Bozza et al., VBMicroLensing, arXiv:2410.13660v1; A&A 694 A219 (2025)
Worked example with a half-radius offset
Let and . One milliarcsecond is one thousandth of an arcsecond. The dimensionless source offset is one half. Substituting it into the quadratic gives
The image separation is . It is larger than twice the Einstein radius. This is a useful check: the two-image separation is , which approaches twice the Einstein radius as the source approaches perfect alignment.
At exact alignment the direction of the line is no longer unique. Every direction around the lens supplies a solution, and a point source has an ideal ring. A finite star fills an annular area; the next chapter adds its light across the full disk.
Reading: Bozza et al., VBMicroLensing, arXiv:2410.13660v1; A&A 694 A219 (2025)
The area map supplies the brightness
Imagine a tiny rectangular patch on the source. The lens stretches it differently along the radial direction and along the ring. A derivative measures either local stretch: how a small change at the image maps to a change at the source. Multiplying the two stretches gives the signed area ratio.
An image’s signed magnification is . The sign records orientation. A negative image is mirrored, not a negative amount of light. Its observed contribution is the absolute value. Sum the contributions of both images to get the point-source magnification:
For the half-radius example, the two contributions are and . Their sum is . The outer image has positive orientation; the inner image is mirrored. Far from the lens the total approaches one.
Reading: Bozza et al. (2018), VBBinaryLensing finite-source methods · Bozza et al., VBMicroLensing, arXiv:2410.13660v1; A&A 694 A219 (2025)
What the ring scale can tell us about mass
The Einstein radius combines mass and distance. A larger mass makes a larger ring, but changing also changes which mass gives the same angular scale. Measuring the ring or an astrometric shift therefore supplies a relation between mass and distance.
A light-curve timescale introduces relative angular speed : . A small lens moving slowly can share an event length with a larger lens moving faster. In chapter three we combine source size and parallax to obtain additional scales.
The useful habit is to ask which quantity an observation measures directly. Image angles give angular geometry. A duration gives an angular scale divided by a speed. A mass in physical units needs the remaining information.
Reading: Dong et al., A Saturn-mass microlensing object, arXiv:2601.00057v1; Science