Skip to main content
Sandbox Physics

L33 · Four fields, one focus

Coherent Beam Combining

In coherent beam combining, does locking the phases fix every error? No. Piston locking aligns each beam’s overall oscillation phase. It cannot point the beams in the same direction, equalize their powers or fill gaps across a tiled pupil. The power in the chosen output port and in a fixed focal region still have to be measured separately.

Compare the focus before and after phase control. Try tilted beams, a weak channel and two pupil layouts; follow power into the focal bucket and rejected ports.

Interactive modelCoherent Beam Combining
Feedback iteration—\text{—}
On-axis phase fidelity at current tilt—\text{—}
Second-channel piston—\text{—}
Third-channel piston—\text{—}
Fourth-channel piston—\text{—}
Exit pupil architecture—\text{—}
Phase feedback—\text{—}
Captured camera pixels—\text{—}
Selected port / input power—\text{—}
Rejected ports / input power—\text{—}
All ports / input power—\text{—}
Coherent bucket / input power—\text{—}
Initial bucket / input power—\text{—}
Incoherent reference bucket—\text{—}
Captured controller iteration—\text{—}

Physics tutorial

Phase control is only one part of combining

BackgroundSeparate amplifiers seeded by the same laser can share one frequency, yet their beams arrive with different phases and tilts.

Why it mattersFour beams can deliver the same total power yet produce a dim, split focus. Their relative oscillation phases decide where interference sends that power.

Start with the essentials

Focus question
Does locking the phases fix every combining error?
One-sentence intuition
Piston locking can concentrate the light, but beam pointing and unequal amplitudes still determine how much reaches the chosen focal region.

Core mathematical model

Field of each channel

Ej=Aju(qj)eiΦjΦj=ϕj+kϑj⋅qjqj=r−rj\begin{aligned}E_j&=A_j u(\boldsymbol q_j)e^{i\Phi_j}\\\Phi_j&=\phi_j+k\boldsymbol\vartheta_j\cdot\boldsymbol q_j\\\boldsymbol q_j&=\boldsymbol r-\boldsymbol r_j\end{aligned}

Each channel has its own amplitude, piston phase and tilt. The feedback loop and the camera both work from these same values.

Tiled pupils seen through a Fourier lens

Etile=∑j=14EjIf∝∣F[Etile]∣2\begin{aligned}E_{\rm tile}&=\sum_{j=1}^{4}E_j\\I_f&\propto|\mathcal F[E_{\rm tile}]|^2\end{aligned}

The pupils do not overlap, so the total power is the sum of the channel powers. Interference only moves energy around in the focal plane.

Filled aperture: a lossless four-port network

Ep=12∑jHpjEjHHT=4I∑pPp=∑jPj\begin{aligned}E_p&=\tfrac12\sum_j H_{pj}E_j\\H H^{\mathsf T}&=4\mathbb I\\\sum_p P_p&=\sum_j P_j\end{aligned}

Each output port adds the four fields with its own pattern of Hadamard signs. Any mismatch between channels sends power into the rejected ports.

Dither control from one measured signal

J=∣∑jcjeiϕj∣2(∑jcj)2Gj=J(ϕj+ϵ)−J(ϕj−ϵ)2ϵϕjn+1=ϕjn+3KGj\begin{aligned}J&=\frac{|\sum_j c_j e^{i\phi_j}|^2}{(\sum_j c_j)^2}\\G_j&=\frac{J(\phi_j+\epsilon)-J(\phi_j-\epsilon)}{2\epsilon}\\\phi_j^{n+1}&=\phi_j^n+3KG_j\end{aligned}

The controller corrects the piston phases one channel at a time, using a single measured number for each step. It leaves the tilt unchanged.

Incoherent reference

⟨If⟩inc=s2∑j∣F[Ej]∣2s={1tiled1/2filled port\begin{aligned}\langle I_f\rangle_{\rm inc}&=s^2\sum_j|\mathcal F[E_j]|^2\\s&=\begin{cases}1&\text{tiled}\\1/2&\text{filled port}\end{cases}\end{aligned}

Averaging over an ensemble removes the interference cross terms. The curve is that average, not one noisy frame.

Power inside a fixed bucket

ηB=∫∣ρ∣<15 μmIf d2ρPinput\eta_B=\frac{\int_{|\boldsymbol\rho|<15\,\mu\mathrm m}I_f\,d^2\rho}{P_{\rm input}}

Changing the array spacing changes the sidelobes, even after the phases are locked.

Common difficulties

A brighter focus means more power

Typical misconceptionLocking the phases creates extra light energy.

Better mental modelNo power is created. In the lossless network, the four output ports together always carry the input power. In a tiled array, interference only moves power from place to place.

One good number means everything is fixed

Typical misconceptionIf the on-axis phase fidelity is perfect, all the beams must be aligned.

Better mental modelThe metric is normalized at the current tilt, so it can reach its best value while the beams still point apart. Check the actual bucket power on the camera, and compare it with the result after manual alignment.

Run the experiment

  1. 01

    Compare the acquired spots

    Choose Coherent focus. The initial camera and the camera after forty controller iterations are acquired automatically.

    What to observe: The focus concentrates as the relative phases align. Both images use the same fixed brightness map; the ring marks the same fifteen-micrometre bucket.
  2. 02

    Leave the beams tilted

    Choose Locked but tilted and compare the phase metric with bucket power. Open Advanced controls and choose Manually remove tilt.

    What to observe: A high phase metric at the current tilt can coexist with a weak bucket signal. Steering can add power to the bucket after piston locking has finished.
  3. 03

    Follow the rejected power

    Choose Single-port combining, then weaken the fourth channel. Compare Bright sidelobes with the tiled default separately.

    What to observe: Imbalance leaves power in the three rejected ports. A sparse tiled pupil instead redistributes more of the focal pattern into sidelobes.
FeedbackSomething broken, confusing, or missing on this page?Tell us
What kind of feedback?

Sent with this page’s address, its Lab ID, the site language and your device type. Please leave out personal details. Feedback is kept for up to 12 months.Privacy policy