Skip to main content
Sandbox Physics

L14 · Saturation, loss and useful power

Output Coupler Optimization

Which output mirror gives a laser the most output power? One that lets out a moderate fraction of the light. With too little transmission the light stays trapped inside and internal losses eat it; with too much, the gain cannot keep up and the laser stops. Where the best value lies depends on the gain and on the internal loss.

A more transmissive output mirror lets more light out but weakens the light circulating inside. Record power-meter readings as you change the mirror, pick the best setting you measured, and compare it with the optimum of the continuous model.

Interactive modelOutput Coupler Optimization
Steady oscillator state—\text{—}
Recorded mirror settings—\text{—}
Circulating power before gain—\text{—}
Power incident on output mirror—\text{—}
Useful output power—\text{—}
Internal dissipated power—\text{—}
Stimulated power added per round trip—\text{—}
Saturated intensity log gain—\text{—}
Total intensity log loss—\text{—}
Largest transmission at threshold—\text{—}
Useful share of stimulated power—\text{—}
Power-balance residual—\text{—}
Low-loss optimum estimate—\text{—}
Continuous reference optimum transmission—\text{—}
Continuous reference peak output—\text{—}
Best recorded transmission—\text{—}
Best recorded output power—\text{—}

Physics tutorial

A mirror must retain light and let useful power escape

BackgroundIn a saturated laser, the power the gain adds on each round trip equals the power lost inside plus the useful power that leaves through the output mirror. A more transmissive mirror lets a larger fraction out, but the circulating power inside drops.

Why it mattersThe brightest beam inside the cavity does not necessarily deliver the most useful power. A fully closed mirror delivers none.

Start with the essentials

Focus question
How does the best output mirror change when gain or internal loss changes?
One-sentence intuition
The best mirror lies between trapping the light inside and letting out so much that lasing stops. To find it, fix the plane where circulating power is measured, follow every survival factor around the ring, and compare recorded outputs with the medium held fixed.

Core mathematical model

Round-trip survival and the lasing threshold

S=(1−Li)(1−T)ℓ=−ln⁡SG0>ℓfor lasing\begin{aligned}S&=(1-L_i)(1-T)\\\ell&=-\ln S\\G_0&>\ell\quad\text{for lasing}\end{aligned}

The gain is the logarithm of the intensity growth over one full round trip. Internal loss and transmission are power fractions, so the fractions that survive each of them multiply.

Gain saturation in steady state

G(P)=G01+P/PsP=Psmax⁡ ⁣(0,G0ℓ−1)eG(P)S=1(P>0)\begin{aligned}G(P)&=\frac{G_0}{1+P/P_s}\\P&=P_s\max\!\left(0,\frac{G_0}{\ell}-1\right)\\e^{G(P)}S&=1\quad(P>0)\end{aligned}

The circulating power is taken just before the gain element. Above threshold, the saturated gain is pinned at the total logarithmic loss.

Output uses the power arriving at the mirror

POC=P/(1−T)Pout=TPOCPgain,out=POC/(1−Li)Ploss=LiPgain,out\begin{aligned}P_{\rm OC}&=P/(1-T)\\P_{\rm out}&=TP_{\rm OC}\\P_{\rm gain,out}&=P_{\rm OC}/(1-L_i)\\P_{\rm loss}&=L_iP_{\rm gain,out}\end{aligned}

In the ring sequence, the reference circulating power comes after the coupler. Multiplying it directly by the transmission would use the power at the wrong plane, and the error matters once the coupling is appreciable.

Power balance around the ring

ΔPstim=Pgain,out−PΔPstim=Pout+Plossηextraction=PoutΔPstim\begin{aligned}\Delta P_{\rm stim}&=P_{\rm gain,out}-P\\\Delta P_{\rm stim}&=P_{\rm out}+P_{\rm loss}\\\eta_{\rm extraction}&=\frac{P_{\rm out}}{\Delta P_{\rm stim}}\end{aligned}

This is a steady-state balance of optical power, not an electrical or pump conversion efficiency. No calibrated pump power enters the model.

Threshold and a low-loss estimate

Tth=1−e−G01−LiPout≃PsT ⁣(G0Li+T−1)Topt,low≃G0Li−Li\begin{aligned}T_{\rm th}&=1-\frac{e^{-G_0}}{1-L_i}\\P_{\rm out}&\simeq P_sT\!\left(\frac{G_0}{L_i+T}-1\right)\\T_{\rm opt,low}&\simeq\sqrt{G_0L_i}-L_i\end{aligned}

If the threshold transmission comes out negative, no mirror can keep the laser oscillating. The square-root estimate drops higher-order corrections to the survival factors, so compare it only when losses are small.

Best sample versus continuous optimum

Trecorded=argmax⁡Tj Pout,jTreference=argmax⁡0≤T≤0.7 Pout(T)\begin{aligned}T_{\rm recorded}&=\underset{T_j}{\operatorname{argmax}}\,P_{{\rm out},j}\\T_{\rm reference}&=\underset{0\le T\le0.7}{\operatorname{argmax}}\,P_{\rm out}(T)\end{aligned}

The first line picks from recorded values only. The second searches the model over a continuous range; a scan in whole-percent steps can miss a true maximum that falls between samples.

Common difficulties

A bright cavity does not mean a bright output

Typical misconceptionThe more reflective the output mirror, the more power comes out.

Better mental modelA fully closed mirror lets nothing out. Optimize the useful output, not the power circulating inside.

Extraction is not pump efficiency

Typical misconceptionA high useful fraction means the pump or power supply is efficient.

Better mental modelThe fraction only compares the light extracted with the stimulated power added. This model does not calibrate the pump.

The best sample is not the exact optimum

Typical misconceptionThe best whole-percent setting must be the exact optimum.

Better mental modelThe continuous peak can fall between two samples. Keep the measured choice and the ideal reference apart.

Run the experiment

  1. 01

    Close the mirror

    Choose Closed output mirror and compare the circulating power with the useful output.

    What to observe: A saturated field can still persist inside, but all the power the gain adds is dissipated internally, and the useful output is zero.
  2. 02

    Extract too much

    Choose Too much extraction and lower the transmission until lasing starts again.

    What to observe: Lasing needs the small-signal gain to exceed the total logarithmic loss. Below threshold there is no steady stimulated output.
  3. 03

    Choose from a measured scan

    Press Scan 71 settings, then Use best recorded mirror, and compare the result with the continuous reference.

    What to observe: The best recorded output comes close to the model's peak, but the chosen transmission is still one of the sampled settings.
  4. 04

    Change the loss and the gain

    Compare High parasitic loss with Stronger available gain, and repeat the acquisition each time.

    What to observe: The best transmission moves. Changing the saturation power scales every power in watts but leaves the best transmission unchanged.
FeedbackSomething broken, confusing, or missing on this page?Tell us
What kind of feedback?

Sent with this page’s address, its Lab ID, the site language and your device type. Please leave out personal details. Feedback is kept for up to 12 months.Privacy policy