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Sandbox Physics

L21 · Distributed gain and feedback

Fiber Laser & FBG Cavity

Does more fiber always give more useful output? No. The pump is absorbed as it travels along the fiber. Past the point where it is used up, extra fiber adds loss instead of gain. The gratings at the two ends must also reflect the same wavelength; shift the output grating's wavelength and the feedback can fail completely.

Build a fiber laser between two fiber Bragg gratings, check the pump and signal power at any point along the fiber, and record output versus pump. Shift the output grating to take away the feedback at the fixed laser wavelength.

Interactive modelFiber Laser & FBG Cavity
Front signal output—\text{—}
Rear signal escape—\text{—}
Absorbed pump—\text{—}
Residual pump—\text{—}
Zero-field round-trip log margin—\text{—}
Relative mirror-boundary error—\text{—}
Output FBG reflection at held wavelength—\text{—}
Bare-fiber longitudinal spacing—\text{—}
Position probe—\text{—}
Local excited fraction—\text{—}
Local pump power—\text{—}
Local forward signal—\text{—}
Local backward signal—\text{—}
Local net intensity gain—\text{—}
Quantum-defect minimum channel—\text{—}
Forward nonlinear phase diagnostic—\text{—}
Captured pump settings—\text{—}
Captured final-step slope—\text{—}
Held-mode branch—\text{—}

Physics tutorial

Distributed reservoirs and mirror boundaries

BackgroundIn a fiber laser the gain is spread along the doped fiber, and two fiber Bragg gratings at the ends provide the feedback. Look at the pump and signal power at any point, record output versus pump, and shift the output grating to remove the feedback at the signal wavelength.

Why it mattersBefore you draw a conclusion about a design, link each part of the fiber to the powers the model actually computes there.

Start with the essentials

Focus question
Does more fiber always give more useful output?
One-sentence intuition
The laser runs only when the gain along the fiber and the reflections at both gratings together bring the signal back to the same power after a round trip.

Core mathematical model

Population balance at each point

f=Wpa+WsaWpa+Wpe+Wsa+Wse+τ−1Wjk=ΓjσjkPjhνjA\begin{aligned}f&=\frac{W_{pa}+W_{sa}}{W_{pa}+W_{pe}+W_{sa}+W_{se}+\tau^{-1}}\\ W_{jk}&=\frac{\Gamma_j\sigma_{jk}P_j}{h\nu_j A}\end{aligned}

Absorption fills the upper manifold; stimulated and spontaneous emission empty it. The signal power here is the sum of both directions.

One population sets pump absorption and signal gain

dPpdz=−ΓpN[σpa(1−f)−σpef]Ppgs=ΓsN[σsef−σsa(1−f)]−αs\begin{aligned}\frac{dP_p}{dz}&=-\Gamma_pN[\sigma_{pa}(1-f)-\sigma_{pe}f]P_p\\ g_s&=\Gamma_sN[\sigma_{se}f-\sigma_{sa}(1-f)]-\alpha_s\end{aligned}

The pump overlap is the core area divided by the cladding area. A larger core therefore changes the pump overlap as well as the signal intensity.

Signal waves and the two grating conditions

dP+dz=gsP+dP−dz=−gsP−P+(0)=R1P−(0)P−(L)=R2P+(L)\begin{aligned}\frac{dP_+}{dz}&=g_sP_+\\\frac{dP_-}{dz}&=-g_sP_-\\ P_+(0)&=R_1P_-(0)\\ P_-(L)&=R_2P_+(L)\end{aligned}

In this model the product of the forward and backward powers stays constant along the fiber. The solver adjusts the launched forward signal until the condition at the output grating is met.

Threshold with no signal present

M0=ln⁡(R1R2)+2∫0Lgs,0(z) dz\mathcal M_0=\ln(R_1R_2)+2\int_0^L g_{s,0}(z)\,dz

If this zero-field round-trip margin is positive, a saturated lasing solution can exist. Reaching transparency at one point is a weaker condition than reaching threshold for the whole cavity.

Useful power leaves through the front grating

Pout=(1−R2)P+(L)P_{\rm out}=(1-R_2)P_+(L)

Making the output grating reflect almost everything can raise the power inside the cavity and still lower the useful output.

Two diagnostics that do not change the solution

Qqd=(1−λpλs)Pp,absB+=∫0L2πn2P+(z)λsA dz\begin{aligned}Q_{\rm qd}&=\left(1-\frac{\lambda_p}{\lambda_s}\right)P_{p,\rm abs}\\ B_+&=\int_0^L\frac{2\pi n_2P_+(z)}{\lambda_s A}\,dz\end{aligned}

The first is the minimum power set by the photon-energy difference between absorbed pump and signal. The second is the nonlinear phase of the forward signal. Neither one changes the steady cavity solution, and neither is a high-power solver.

Common difficulties

More fiber is always better

Typical misconceptionA longer fiber absorbs more pump, so the output has to go up.

Better mental modelA tail that gets almost no pump, together with background loss, can outweigh that extra absorption.

Mismatched gratings mean no laser

Typical misconceptionIf the two gratings are offset, the laser cannot start at any pump power.

Better mental modelThis fixed-wavelength model only checks whether gain beats loss, and enough gain can make up for a weak reflection. It does not solve for other wavelengths.

Run the experiment

  1. 01

    Break and restore feedback

    Choose Gratings mismatched, then set Output Bragg offset to zero.

    What to observe: The only thing that changes is the output grating's reflection at the fixed signal wavelength.
  2. 02

    Follow the powers along the fiber

    In Working cavity and in Long fiber, move the probe along the fiber with Probe position fraction.

    What to observe: The leftover pump, the local excitation and the backward signal all come from the same solution.
  3. 03

    Measure the useful output

    Press Acquire pump sweep for Working cavity and for Nearly closed output.

    What to observe: The signal stored in the cavity and the useful output do not have to rise together.
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