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Sandbox Physics

FR21 · Growth and dilution

Patterns on a growing domain

What happens to a chemical pattern when its domain expands? Growth stretches the available wavelengths and dilutes each substance over a larger area. Even when the total amount stays constant, concentration falls, which changes the reaction and the pattern.

Expand the same patterned square and watch old peaks stretch and new ones emerge. Compare concentration with total amount, then turn reactions off to isolate dilution.

Interactive modelPatterns on a growing domain
Growth time1010
Mean concentration11
Total activator amount256256
Physical side length18.618.6

SIMULATION RECORD AND ANALYTIC REFERENCE

Concentration falls as the area increases

Cyan: mean activator concentration relative to the prepared state. Gold: total activator amount relative to that state. Reactions can change total amount; switch to Conserved amount to remove both source and sink.

The field uses one fixed color scale: dark blue at zero, cyan near one and amber at 2.5 and above. Opposite edges touch.

Read the derivation and worked examples

Physics tutorial

Follow material, then count molecules

BackgroundWhen the patterned material expands, neighboring material points move apart. The same chemical amount occupies more area, so its concentration falls unless reactions replace it.

Why it mattersChanging the picture size alone misses this dilution. Following the material lets us keep track of diffusion, chemical production and the growing area together.

Start with the essentials

Focus question
How can concentration fall even when no chemical is lost?
One-sentence intuition
Concentration is amount per area; the area changes during growth.

Core mathematical model

Coordinates attached to the material

x=L(t)ξ,y=L(t)η,g=L˙Lx=L(t)\xi,\qquad y=L(t)\eta,\qquad g=\frac{\dot L}{L}

The material coordinates remain fixed as the physical square grows. Length and time are dimensionless, and the growth rate is the fractional increase of side length per unit time.

Reaction, diffusion and area dilution

∂tu∣ξ,η=DuL(t)2∇ξ,η2u+f(u,v)−2gu\left.\partial_t u\right|_{\xi,\eta}=\frac{D_u}{L(t)^2}\nabla_{\xi,\eta}^2u+f(u,v)-2gu

The factor of two comes from growth in two directions. The substrate has the same dilution term, with its own diffusivity and reaction rate.

Total amount on the square

Mu=L(t)2⟨u⟩,dMudt=L(t)2⟨f(u,v)⟩M_u=L(t)^2\langle u\rangle,\qquad \frac{dM_u}{dt}=L(t)^2\langle f(u,v)\rangle

Periodic diffusion transfers material internally. With all reactions off, the total amount remains constant even though concentration changes.

Common difficulties

Concentration and amount answer different questions

Typical misconceptionA falling concentration means the chemical has disappeared.

Better mental modelAn expanding area can lower concentration without removing any molecules. Multiply mean concentration by the current area to calculate total amount.

The old equilibrium need not remain an equilibrium

Typical misconceptionThe same reaction parameters should preserve the original mean concentration.

Better mental modelGrowth continuously dilutes both species. Their reaction rates respond to the new concentrations, and the combined balance can move away from the fixed-domain equilibrium.

Run the experiment

  1. 01

    Compare the two quantities

    Start with Growing pattern and compare the cyan and gold curves.

    What to observe: Concentration and total amount follow different histories because the area is changing and reactions continue.
  2. 02

    Remove chemical production and loss

    Select Conserved amount.

    What to observe: The gold curve stays at one. The cyan curve decreases as the square expands; all of this decrease comes from dilution.
  3. 03

    Hold the domain still

    Select Fixed domain, then compare with Fast expansion.

    What to observe: The fixed domain retains its original physical spacing. Growth stretches the old pattern and changes which physical wavelengths fit inside the square.

Related experiments and articles

Morphogenesis and reaction–diffusion · Reading path

Reaction, diffusion, growth and active stress

Articles on this path that use this experiment, followed by the other experiments they suggest.

  1. ArticleWhy concentration falls as a tissue grows
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