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Sandbox Physics

E11 · Electron imaging / spectroscopy

SEM Secondary-Electron Topography

Does a brighter surface mean a taller surface? Not necessarily. In a secondary-electron image, brightness depends on how each part of the surface faces the detector: edges glow, slopes turned away fall into shadow, and counting noise adds speckle. Move the detector and the same terrain can look like a completely different object.

Move the side detector around a fixed terrace with three particles on it. Tilt the specimen and change the working distance and landing energy, then compare a saved frame of electron counts with the known height map. Inspecting pixels or changing display gain reuses that same frame. The same terrain can look like a different object.

Interactive modelSEM Secondary-Electron Topography
Saved flank mean counts00
Saved flank contrast0 %0\,\mathrm{\%}
Flank count CNR00
Probe blur proxy0 nm0\,\mathrm{nm}
More measurements and target
Assumed escape depth0 nm0\,\mathrm{nm}
Fixed grain height0 nm0\,\mathrm{nm}
Selected pixel counts00
Selected face—\text{—}
Experiment task—\text{—}

Physics tutorial

Does a brighter surface mean a taller surface?

BackgroundMove the side detector around a fixed terrace with three particles on it. Tilt the specimen and change the working distance and landing energy, then compare the image of electron counts with the true height map. The same terrain can look like a different object.

Why it mattersBefore drawing conclusions about the specimen, see how each instrument setting shapes the measured result.

Start with the essentials

Focus question
Does a brighter surface mean a taller surface?
One-sentence intuition
Moving the detector changes the image even though the specimen stays the same. Edge enhancement, line of sight to the detector and counting noise all affect brightness, so brightness alone is an ambiguous measure of height.

Core mathematical model

Electron counting

N0=Iτ/eNˉij=N0(Gσ∗S)ij\begin{gathered}N_0=I\tau/e\\\bar N_{ij}=N_0(G_\sigma*S)_{ij}\end{gathered}

The ideal signal is yield times collection. An assumed isotropic Gaussian blurs it in specimen coordinates, and then counts are sampled with a fixed seed. The 192 by 192 pixel centers span 1 micrometre, and the dwell time applies to each site. This teaching raster stays registered to the specimen, so it leaves out projected foreshortening and the redistribution of a blocked probe.

Side-detector collection estimate

Cside=(0.08+0.55cd)Vcd=max⁡(0,n⋅d)\begin{gathered}C_{\mathrm{side}}=(0.08+0.55c_d)V\\c_d=\max(0,\mathbf n\cdot\mathbf d)\end{gathered}

The direction points from the surface point to the receiving window drawn on the detector. Visibility is zero when that ray points into the surface or the terrain blocks it. This straight-line estimate leaves out field-guided collection around obstacles; in-lens mode uses a separate prescribed estimate. There is no solid-angle or distance calibration.

Contrast and shot-noise test

c=∣N1−N2∣N1+N2CNR=∣N1−N2∣N1+N2\begin{gathered}c=\frac{|N_1-N_2|}{N_1+N_2}\\\mathrm{CNR}=\frac{|N_1-N_2|}{\sqrt{N_1+N_2}}\end{gathered}

Both numbers use the two saved pixels closest to the two chosen flanks of the grain, after blur and counting. The CNR divides the count difference by the independent Poisson noise of the two pixels; it is not the uncertainty of a region average. If the total is zero, the flanks remain unresolved. Display gain and pixel inspection cannot change this test.

Common difficulties

Reading brightness as height

Typical misconceptionA bright rim is a taller rim, and an SEM image is already a height map.

Better mental modelThe fixed height map and the profile seen by the opposite detector are counterexamples. Both the generation and the collection of secondary electrons depend on geometry, so a quantitative height needs more information than brightness.

Run the experiment

  1. 01

    Predict the bright flank

    Predict which flank of the central grain will brighten when the detector turns by half a revolution. Compare Surface target and Opposite detector before changing the specimen tilt.

    What to observe: The image changes even though the specimen stays the same. Edge enhancement, line of sight to the detector and counting noise all affect brightness, so brightness is an ambiguous measure of height.
  2. 02

    Meet the imaging target

    Reach at least 15 percent contrast between opposite flanks, a CNR of at least 5 and a probe-blur estimate below 8 nm. Then reverse the detector and explain why the height map stays the same.

    What to observe: Press Check target; the test uses the saved counts. Then inspect pixels with the row and column controls. Changing the gain or camera view reuses the same saved frame. The known height map is a separate input, not something recovered from brightness.
  3. 03

    Separate the causes of contrast

    Switch to In-lens collection, then raise the working distance and lower the current. Change the gain and confirm that the count-based task result does not change. Tell apart directional shading, blur and counting noise.

    What to observe: The image is a teaching raster laid out in specimen coordinates: a 192 by 192 grid of sites spanning 1 micrometre, with the same dwell time at each site. It leaves out the foreshortening of a projected image and does not redistribute the probe where terrain blocks it. Yield, isotropic blur and collection are all assumed. Opaque terrain blocks both direct excitation and side collection; axial collection uses a field-guided approximation. Saved counts use a fixed random seed, drawn from a Poisson distribution below a mean of 40 and from a Gaussian approximation above it. The detector field, charging, calibrated efficiency and recovering height from the image are not modeled.
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