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Sandbox Physics

Electromagnetism · force and energy

Charged Particle

Launch into uniform electric and magnetic fields. Replay the recorded path, reverse the charge, and compare kinetic energy with electric work in the same flight record.

Interactive modelCharged Particle
Recorded speed—\text{—}
Instantaneous magnetic radius—\text{—}
Cyclotron angular frequency—\text{—}
Kinetic energy—\text{—}
Electric work—\text{—}
Energy balance residual—\text{—}

FOLLOW THE EVIDENCE

Account for the energy

Both plots use the frozen flight record. Electric work is calculated from the displacement, independently of the velocity update. A residual reports numerical error, including the position integration error.

ΔK=WE,WE=q E⋅(r−r0)\Delta K=W_E,\qquad W_E=q\,\mathbf E\cdot(\mathbf r-\mathbf r_0)

The border is a display frame, not an electrode or a chamber wall. Position scales adapt to the full recorded path; particle size and vector lengths are exaggerated. Positive normal magnetic field follows the right-handed convention.

Physics tutorial

Charged particles: electric fields change energy, magnetic fields turn motion

BackgroundA charged particle responds to electric and magnetic fields. Electric force follows E, while magnetic force comes from the cross product of velocity and B.

Why it mattersMass spectrometers, cyclotrons, plasma confinement, and the Hall effect all use the same Lorentz force.

Start with the essentials

Focus question
Why can a pure magnetic field bend a path into a circle without making the particle faster?
One-sentence intuition
Magnetic force stays perpendicular to velocity and does no work; the electric field directly changes kinetic energy.

Core mathematical model

Work-energy check

K(t)−K(0)=q E⋅[r(t)−r(0)]K(t)-K(0)=q\,\mathbf E\cdot[\mathbf r(t)-\mathbf r(0)]

Uniform-field electric work comes from displacement. Compare it with the kinetic change computed from recorded velocity. The magnetic field does no work.

Lorentz force

F=q(E+v×B)\mathbf F=q(\mathbf E+\mathbf v\times\mathbf B)

The cross product sets magnetic magnitude and direction; charge sign reverses the total force.

Gyration and drift scales

rc=mv⊥∣q∣B,vD=E×BB2r_c=\frac{mv_\perp}{|q|B},\qquad\mathbf v_D=\frac{\mathbf E\times\mathbf B}{B^2}

Mass and perpendicular speed enlarge the orbit; E×B\mathbf E\times\mathbf B drift is independent of mass and charge sign for nonzero charge and magnetic field.

Common difficulties

A magnetic field does not increase speed

Typical misconceptionAny sustained force must make the particle faster.

Better mental modelA perpendicular force rotates velocity; power q(v×B)⋅vq(\mathbf v\times\mathbf B)\cdot\mathbf v is always zero.

Negative charge reverses the right-hand result

Typical misconceptionv×B\mathbf v\times\mathbf B is the force direction for every particle.

Better mental modelv×B\mathbf v\times\mathbf B gives the direction for positive charge; q<0q<0 reverses it.

Run the experiment

  1. 01

    Establish pure gyration

    Choose Pure magnetic circle and scrub the recorded time.

    What to observe: Speed stays fixed while the path becomes circular.
  2. 02

    Reverse one sign

    Reverse charge and launch; compare the recorded path.

    What to observe: Rotation reverses while radius stays similar.
  3. 03

    Add a perpendicular electric field

    Choose Crossed-field drift, edit the electric field, then launch a new flight.

    What to observe: The orbit center develops steady sideways motion.
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