Skip to main content
Sandbox Physics

E16 · Reflection orientation mapping

EBSD: From Bands to Grains

Can you trust an EBSD grain map made with a bad calibration? No, and it may not look wrong. Each point's orientation comes from matching its diffraction pattern against candidate phases. The match needs enough signal, the right candidates and a calibrated pattern center, which tells the software where the screen sits relative to the beam spot. A bad calibration still paints a confident map, so report how well each point fits and how many were rejected.

Calibrate the pattern center and index the stored Kikuchi patterns. Then compare the beam-direction IPF, phase and grain maps with an independent check against the known specimen.

Interactive modelEBSD: From Bands to Grains
Indexed one-axis rotation—\text{—}
Indexed teaching phase—\text{—}
Accepted fraction of all pixels—\text{—}
Independent check of phase and angle inputs—\text{—}
More measurements and target
Selected stored pattern counts—\text{—}
Selected detector pixel counts—\text{—}
Best candidate correlation—\text{—}
Best versus runner-up score gap—\text{—}
Accepted-pixel mean angular error—\text{—}
Assumed footprint FWHM along tilt—\text{—}
Incident dose per scan pixel—\text{—}
Experiment target—\text{—}

Physics tutorial

EBSD: From Bands to Grains

BackgroundEBSD scans an electron beam across a tilted specimen and records a Kikuchi pattern at every point. Band positions encode the crystal orientation and band widths depend on the lattice spacing, so the patterns build maps of phases and grains.

Why it mattersThe task asks for a map you can trust: at least 90 percent of pixels indexed, the correct phase and a rotation within 2 degrees in at least 90 percent of all pixels, and a mean angular error within 2 degrees for the accepted pixels.

Start with the essentials

Focus question
Can you trust an EBSD grain map made with a bad calibration?
One-sentence intuition
An indexing result depends on calibrated geometry, enough counts and a suitable family of candidates.

Core mathematical model

Cone edges on the detector

dhkl=a/h2+k2+l2∣s^⋅n^hkl∣=sin⁡θB=λ/(2dhkl)\begin{aligned}d_{hkl}&=a/\sqrt{h^2+k^2+l^2}\\|\widehat{\mathbf s}\cdot\widehat{\mathbf n}_{hkl}|&=\sin\theta_B=\lambda/(2d_{hkl})\end{aligned}

Ray directions that meet this condition lie on two Bragg cones. The trace of the lattice plane midway between them is the band center line; band intensity is prescribed.

Count first, index second

μj=Iτe η Bj∑kBkc^=arg max⁡c  (N−N‾)⋅(Tc−T‾c)∥N−N‾∥ ∥Tc−T‾c∥\begin{aligned}\mu_j&=\frac{I\tau}{e}\,\eta\,\frac{B_j}{\sum_k B_k}\\\widehat c&=\underset{c}{\operatorname{arg\,max}}\;\frac{(\mathbf N-\overline N)\cdot(\mathbf T_c-\overline T_c)}{\|\mathbf N-\overline N\|\,\|\mathbf T_c-\overline T_c\|}\end{aligned}

Each scan point stores one detector pattern. Indexing compares those counts with every entry in the stated dictionary of orientations and phases and keeps the highest normalized correlation.

Compare indexed neighbors

δ=min⁡(r,90∘−r)r=∣ϕ1−ϕ2∣ mod 90∘\begin{aligned}\delta&=\min(r,90^\circ-r)\\r&=|\phi_1-\phi_2|\bmod90^\circ\end{aligned}

For this one-axis cubic family only, the angle difference between two pixels of the same phase is reduced by the 90 degree symmetry. Angles are never compared across different phases.

Common difficulties

Map color is not a full orientation

Typical misconceptionA beam IPF map alone proves every orientation and phase.

Better mental modelThe search covers only the stated one-axis family and the fictional phases. Treat dark pixels and narrow margins between candidates as limits of the result, and look at the stored patterns.

Run the experiment

  1. 01

    Predict before indexing

    Select a stored pixel and inspect its detector pattern. Compare it with the separately labeled input.

    What to observe: Band positions encode orientation; band widths also depend on the lattice spacing.
  2. 02

    Calibrate and search

    Try the wrong-center preset, then set the center error to zero. Sweep binning without reacquiring.

    What to observe: A wrong geometry can reject a clean pattern, and coarse binning wipes out the difference in band widths.
  3. 03

    Read the maps

    Compare beam IPF, phases, connected grains and neighbor disorientation. Select a boundary pixel.

    What to observe: Unindexed pixels stay dark, and grains are segmented from the recovered data only.
  4. 04

    Test the tradeoff

    Use short exposure and an overly strict threshold.

    What to observe: A high rejection threshold does not make the missing pixels trustworthy.
FeedbackSomething broken, confusing, or missing on this page?Tell us
What kind of feedback?

Sent with this page’s address, its Lab ID, the site language and your device type. Please leave out personal details. Feedback is kept for up to 12 months.Privacy policy