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FR40 · Prandtl–Tomlinson model

Atomic Stick-Slip: How an AFM Tip Feels Friction

Why does a tip dragged across a crystal move in jumps? Because the spring holding the tip is too soft to stop it catching in the hollows between atoms. The tip waits in one hollow while the spring stretches, then the hollow vanishes and it falls into the next. The energy released in each fall becomes heat, and that heat per atom spacing is the friction. With the parameters fitted to salt, the slow, cold tip slips at about 0.68 nN and averages 0.53 nN.

Drag a spring-held tip across a salt crystal and watch it stick, then jump one atom ahead. The sawtooth force and the heat each jump leaves are the friction.

Interactive modelAtomic Stick-Slip: How an AFM Tip Feels Friction
Stick-slip parameter η\eta11.511.5
Mean friction force0.324 nN0.324\,\mathrm{nN}
Heat per lattice period0.809 eV0.809\,\mathrm{eV}
Mean slip length1 a1\,a
Energy the tip feels now
Lateral force: the sawtooth
Where the work goes

Physics tutorial

Friction one atom at a time

BackgroundAn atomic force microscope drags a sharp tip across a surface while a soft cantilever holds it. On a clean crystal the measured lateral force is not steady. It rises slowly, drops suddenly, and repeats with the spacing of the surface atoms. That sawtooth is friction seen at its smallest scale.

Why it mattersThe Prandtl–Tomlinson model explains the sawtooth with only a spring and a wavy potential. It says when a tip sticks, how much force it needs before it jumps, and where the work done by the scanner goes. It is the starting point for almost every later model of atomic friction.

Start with the essentials

Focus question
Why does a tip dragged across a crystal move in jumps?
One-sentence intuition
While the spring is soft compared with the curvature of the substrate potential, the tip has more than one place to rest. It stays in its well while the spring stretches, until that well disappears and the tip falls into the next one. The energy released in the fall turns into heat, and that heat per period, divided by the lattice period, is the friction force.

Core mathematical model

Energy of the tip

E(x;X)=−U0cos⁡2πxa+k2(x−X)2E(x;X)=-U_0\cos\frac{2\pi x}{a}+\frac{k}{2}(x-X)^{2}

The tip at xx feels the substrate with amplitude U0U_0 and period aa, and a spring of stiffness kk ties it to the scanner at XX. This is Eq. 1 of Sang, Dubé and Grant (2001).

When the tip can stick

η=4π2U0ka2>1\eta=\frac{4\pi^{2}U_0}{k a^{2}}>1

With U0=0.27 eVU_0=0.27\,\mathrm{eV}, k=0.93 N m−1k=0.93\,\mathrm{N\,m^{-1}} and a=0.4 nma=0.4\,\mathrm{nm} the value is η=11.5\eta=11.5. Below 1 the energy has a single minimum for every scanner position, so the tip follows smoothly and the zero-temperature friction vanishes.

Friction from the energy ledger

⟨F⟩=Qperioda\langle F\rangle=\frac{Q_{\text{period}}}{a}

Over many periods the spring and the tip return to the same state, so all work done by the scanner leaves as heat QperiodQ_{\text{period}}. At room temperature and 100 nm s−1100\,\mathrm{nm\,s^{-1}} the simulated tip gives 0.324 nN0.324\,\mathrm{nN}, so each period leaves about 0.81 eV0.81\,\mathrm{eV}.

Common difficulties

The jump is the friction

Typical misconceptionFriction is the force the tip feels while it rubs against each atom.

Better mental modelThe substrate force averages to zero over a period. What remains is the energy that the slip releases and the damping removes; without slips, a slowly dragged tip returns all the work it receives.

Heat makes friction larger

Typical misconceptionA warmer tip should rub harder.

Better mental modelThermal kicks let the tip hop over the barrier before the well vanishes, so it slips at a smaller force. In this model room temperature lowers the friction from 0.53 nN to about 0.32 nN at 100 nm/s.

Run the experiment

  1. 01

    Watch one slip

    Choose Cold tip slips at the fold and watch the force chart and the energy chart together.

    What to observe: The force climbs to about 0.68 nN, the barrier ahead shrinks to zero, and the tip falls one lattice period. The mean force is about 0.53 nN, on the T=0T=0 reference.
  2. 02

    Predict, then soften the substrate

    Guess what happens when η\eta drops below 1, then choose Smooth sliding.

    What to observe: At 0.02 eV, η=0.85\eta=0.85: the sawtooth disappears, the tip follows the scanner and the mean friction falls to almost nothing.
  3. 03

    Explain longer jumps

    Choose Long slips, where the damping is ten times lighter, and read the slip length.

    What to observe: The tip overshoots and lands two wells ahead. Because it releases less energy per period, the mean friction drops to about 0.37 nN.

Related experiments and articles

Nanofriction · Reading path

From one sticking tip to a twisted flake that glides

Articles on this path that use this experiment, followed by the other experiments they suggest.

  1. ArticleHow large friction is at a single atomic contact
  2. ArticleHow the Tomlinson model explains stick-slip
  3. ArticleFriction as the energy lost in each slip
  4. ArticleThermolubricity and the limits of rate theory
  5. LabThermal Friction: Why Faster Scans Rub HarderRaise the damping and see when rate theory is accurate
  6. ArticleReading the 2013 friction-modelling review by Vanossi and co-workers, section by section
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