How baryon density and extra radiation move the light elements
Sandbox Physics ·
Near the standard point each light-element abundance responds to its inputs like a power law, and the exponents decide what each observation can measure. Deuterium scales as η−1.6, so the observed D/H fixes the baryon density to better than one percent. Helium barely responds to η but grows by about 0.013 per extra neutrino-like species, so it bounds extra radiation. Nuclear rate errors add in quadrature: in the tutorial network they give 0.7 percent on D/H, set mainly by d(p,γ)3He, and 1.8 percent on lithium-7, far too little to explain the factor of three between predicted and observed lithium.
This chapter builds on When neutrons and protons stop turning into each other and Why deuterium waits for the universe to cool. You need logarithms and the idea of a derivative as the ratio of two small changes. Standard deviations and adding independent errors in quadrature are explained where they are used. By the end you should be able to compute a logarithmic sensitivity from two runs, invert an observed abundance into a baryon density with an error bar, turn a helium measurement into a bound on extra radiation, and build an error budget from rate uncertainties.
Logarithmic sensitivity
Let X be an abundance and p an input: the baryon-to-photon ratio η, the number of neutrino-like species Nν, the neutron lifetime or a reaction rate. The logarithmic sensitivity
SX,p=∂lnp∂lnX
is the percentage change in X per percent change in p, all other inputs fixed. If S is constant over a range, X∝pS there. Sensitivities are convenient because they do not depend on units, and because they turn small fractional changes into a linear sum:
XδX≃p∑SX,ppδp.
The method guide computes each S with a central difference. It runs the network with the input multiplied by 1.01 and by 0.99, and divides the change in lnX by ln(1.01/0.99).
Worked example: the neutron lifetime from two runs
The saved runs at τn=860s and 900s give Yp=0.23861 and 0.24675. Then
The 1 percent central difference gives 0.738. Fields, Olive, Yeh and Young list 0.729 in Table II of their 2019 preprint, computed with their full code at η10=6.129.
Table 4.1 Logarithmic sensitivities at η10=6.129 and τn=879.4s. The first number in each cell is the tutorial network, the second is Fields et al., Table II.
input
Yp
D/H
3He/H
7Li/H
η
0.039 / 0.039
−1.618 / −1.597
−0.597 / −0.583
2.058 / 2.094
Nν
0.165 / 0.163
0.400 / 0.396
0.142 / 0.139
−0.269 / −0.280
τn
0.738 / 0.729
0.410 / 0.409
0.146 / 0.144
0.452 / 0.434
d(p,γ)3He
0.000 / 0.000
−0.333 / −0.315
0.376 / 0.376
0.588 / 0.589
3He(α,γ)7Be
0.000 / 0.000
0.000 / 0.000
0.000 / 0.000
0.963 / 0.964
The agreement to within 0.04 is a check of the tutorial network, not new evidence: both calculations share the same physics, and the tutorial's rates are older. The table already says what each element is good for. Deuterium has the largest η exponent. Helium has a tiny η exponent but a sizeable one for Nν. Lithium-7 rises with η, because at high density it is made as beryllium-7, which later captures an electron.
The network gives D/H=2.548×10−5 at η10=6.12. Treat the sensitivity as constant over the small step:
η10=6.12×(2.5082.548)1/1.618=6.12×1.0098=6.180.
A direct bisection on the network gives 6.180 as well. The error has two independent parts. The observational error is 0.29/25.08=1.16 percent of D/H, or 1.16/1.618=0.71 percent of η. The rate error of the prediction, derived below, is 0.69 percent of D/H, or 0.43 percent of η. Independent errors add in quadrature, as the square root of the sum of squares, because their variances add:
The review gives (η10)SBBN=6.040±0.118 (Eq. 24.5), a range it describes as essentially determined by D/H, and 6.104±0.058 from the microwave background without BBN. The tutorial value sits 1.2 standard deviations above the review's BBN value. The difference comes from the predicted D/H at a given η, so from the nuclear rates: the tutorial keeps the 2004 Serpico fits, while the review's value comes from a later analysis that this chapter has not reproduced. Table 4.1 shows why the rates matter so much here: a 1 percent change in d(p,γ)3He moves D/H by a third of a percent, and so the inferred η by a fifth of a percent.
Bounding extra radiation with helium
Any extra relativistic energy, counted as ΔNν additional neutrino species, speeds up the expansion. The network's SYp,Nν=0.165 at Nν=3 converts into an absolute slope
dNνdYp=SYp,NνNνYp=0.165×30.2424=0.0133,
in line with ΔYp≃0.013ΔNν in the review. The direct run with ΔNν=1 gives 0.25485, a rise of 0.0125; the slope falls slowly because the sensitivity is logarithmic in Nν.
Worked example: a one-measurement bound
The review's helium abundance is Yp=0.245±0.003 (Eq. 24.3). The full-physics prediction with three species and the microwave-background baryon density is Yp=0.24691±0.00018 (Fields et al., Eq. 22). Then
The two-sided 95 percent range is roughly −0.59<ΔNν<0.30. One extra fully populated neutrino species lies about five standard deviations away. The review's joint analysis of helium and deuterium gives Nν=2.898±0.141 (Eq. 24.9), which is ΔNν=−0.10±0.14.
Notice what would happen with the tutorial's own prediction, Yp=0.2424. The same arithmetic gives ΔNν=+0.20. The shift of 0.34 species is entirely the weak-rate corrections the tutorial omits, discussed at the end of the first chapter. A bound on new physics is only as good as the absolute prediction it is compared with.
Propagating rate errors
Each nuclear rate fit comes with a one-standard-deviation fractional error σi=δfi/fi that depends on temperature. To first order, and if the rate errors are independent,
(XδX)2=i∑(SX,iσi)2.
The method guide does slightly better than multiplying one number by one sensitivity: it shifts each rate by its full temperature-dependent error and reruns the network. The neutron lifetime is included with an assumed error of 0.5s.
Table 4.2 One-standard-deviation error budget at η10=6.12, in percent. Only the largest contributions are listed.
source
D/H
7Li/H
d(p,γ)3He
0.67
1.21
d(d,n)3He
0.17
0.22
3He(α,γ)7Be
0.00
1.05
7Be(n,p)7Li
0.00
0.40
all, in quadrature
0.69
1.76
As a check that does not rely on the linear formula, the guide also draws 200 random sets of rates and repeats the calculation. The spread is 0.72 percent for D/H and 1.78 percent for lithium-7, close to the quadrature values.
The lithium column answers a question raised in the first article. The review quotes Li/H=(1.45±0.25)×10−10 for metal-poor halo stars (Eq. 24.4) and a BBN-plus-CMB prediction of (4.72±0.7)×10−10 (Eq. 24.10), a factor of 3.3 apart. With S=0.963, closing that gap through 3He(α,γ)7Be alone would need its rate to fall by a factor of about 3.31/0.963≈3.4. The fit's quoted error is 1 to 2 percent at the temperatures where beryllium-7 forms. A drop of about 70 percent is 35 to 70 times that error.
Lab task: weigh the baryons, then test the radiation
Predict. Before moving anything, estimate from Table 4.1 how far you must move the baryon slider to change D/H by 10 percent, and how far the radiation slider to change Yp by 0.003.
Change. Drag the baryon slider until the deuterium curve crosses the centre of the observed band. Then return it to the default and drag the radiation slider until Yp reaches 0.245.
Compare. The first value should be close to η10=6.18; the Lab's coarser time step can move it by about 0.01. For the second, compare your ΔNeff with the +0.20 from the worked example.
Explain. Explain why the radiation slider moves D/H as well as helium, and why the second reading cannot be quoted as a measurement of extra radiation.
Exercises
Use Table 4.1 to predict the change in 7Li/H when η10 goes from 6.12 to 10. The saved run gives 1.09×10−9 from 4.51×10−10. Why does the prediction miss?
A future survey halves the error on D/H to 0.145×10−6 while the rate errors stay the same. What is the new error on η10, and which source of error would then dominate?
Extra radiation also raises D/H. Use Table 4.1 to find the Δη/η that cancels the D/H change from ΔNν=0.5. Then find the resulting helium change. Explain why deuterium alone cannot measure both η and Nν.
Transfer. A colleague's code gives Yp=0.2440 for the standard case. They compare it with Yp=0.245±0.003 and report evidence for ΔNν≈0.08. List what you would check before believing the number.
AnswersShow the answer
ln(10/6.12)=0.491, and 2.058×0.491=1.010, so the predicted factor is e1.010=2.75 and Li/H≈1.24×10−9. The run gives 1.09×10−9, a factor of 2.41. The sensitivity is a local slope. Over this range the average exponent is only ln2.41/0.491=1.79, because the slope itself changes with η: lithium-7 made directly falls while lithium made as beryllium-7 rises, and their mix keeps shifting.
The observational part becomes 0.58/1.618=0.36 percent of η, the rate part stays 0.43 percent, so δη/η=0.362+0.432=0.56 percent, or ±0.034 in η10. The nuclear rates, mainly d(p,γ)3He, would then dominate.
ΔNν=0.5 is ΔlnNν=ln(3.5/3)=0.154; D/H changes by 0.400×0.154=0.062 in ln. Cancelling needs Δlnη=0.062/1.618=0.038, a 3.8 percent higher η. Helium then changes by 0.165×0.154+0.039×0.038=0.027 in ln, about +0.0066. A higher η with extra radiation can reproduce the same D/H, so D/H constrains a combination of the two. Helium, which mostly tracks Nν, or the microwave background, which measures η independently, breaks the degeneracy.
Check the inputs: the baryon density, the neutron lifetime and its error, and the rate set. Check the weak rates: are radiative and finite-mass corrections included? Without them a code sits about 0.005 low, which by itself fakes ΔNν≈+0.3. Check whether Yp is the true mass fraction or four times the helium number fraction. Check numerical convergence by halving the time step. Finally, 0.08/0.23 is a third of a standard deviation: even with a perfect code that sits well inside the noise.
What these numbers do and do not show
All model numbers in this chapter come from the tutorial network and are saved in teaching-values.json and expected.json. They show how sensitivities and error budgets are built; they are not a new determination of η or Nν. Published determinations use a fuller weak-rate treatment, newer rates and joint likelihoods with the microwave background. The guide Reading the BBN evidence on extra radiation and the lithium problem walks through those analyses table by table.