Each energy component accumulates its own phase
Diagonalizing the finite Hamiltonian gives energies and states . In this new basis, the Hamiltonian multiplies each vector by one energy. Project the initial state onto these vectors, rotate each component by its energy-dependent phase, then add them back.
The overlap is the initial amplitude along energy state . Conjugate that energy vector’s components, multiply them by the corresponding initial components, and sum the products.
Relative phases change measurement probabilities. A dimming link represents a changing quantum expectation over flux configurations. A single measurement would give one allowed configuration. It need not resemble a smoothly fading classical rope.
Reading: E. A. Martinez et al. · Sandbox Physics FR04 finite Hamiltonian · Sandbox Physics FR04 original numerical references and reproduction scripts
A resonance you can calculate by hand
Four sites with endpoint sources and electric cutoff one have exactly two physical configurations: the initial string and the state that screens its middle link. Subtract the initial string energy. Their diagonal entries are zero and ; the allowed hop between them is .
Choose , and . The detuning vanishes and pair probability becomes . Transfer is complete at , and the initial string returns at . These full oscillations are exact for this two-state truncated model.
How two charges fluctuate together
Two mean charges do not tell us how their fluctuations occur together. Multiply the two charges within each configuration, then average with its probability. Subtract the product of the separate means to obtain the connected correlation. The Lab observes site one and the second-to-last site, which are and on a six-site chain.
Use the four-site two-state example to calculate it. Let be the probability of the pair configuration. Its middle charges are minus one and plus one; the intact string has zero matter charge at both sites. The separate means are and , but the joint mean is . Their covariance is . At resonance and , both configurations have probability one half, so the covariance is minus one quarter.
The negative sign describes opposite charge fluctuations. After complete transfer both charges are certain, so their connected fluctuation returns to zero. This observable describes charge statistics. A classical mixture can give the same covariance.
Reading: Sandbox Physics FR04 finite Hamiltonian · Sandbox Physics FR04 original numerical references and reproduction scripts
Longer chains have more routes
Six or eight sites allow pairs to appear at different positions and move further. When one link weakens, inspect its neighboring charges. Their changes must obey the local Gauss relation. A spatial field profile often reveals more than a single average.
The closed system conserves energy. A decrease in electric energy can enter the mass term and the expectation of the hopping term. Hopping energy contains coherence between configurations; multiplying the visible pair count by mass does not account for it all.
A return can result from interference among a few energy levels or from propagation to a boundary and back. To identify a finite-volume echo, compare the same local region at different chain lengths and look for a boundary-dependent time shift. A matched local comparison at two chain lengths tests how the boundary contributes to that return.
Define what the pair count is relative to
At half filling and zero total matter charge, occupied even sites and holes on odd sites have equal total counts. The sum of even-site occupations is our bare pair number relative to the staggered product reference. Its expectation can be fractional.
That initial product state is not the interacting vacuum after hopping is turned on. It can develop bare pairs even without external sources. A source-induced increment therefore requires a second, source-free evolution with the same parameter and initial-state convention. Subtracting those curves defines an increment relative to that chosen quench baseline.
Check what must remain unchanged
State norm must remain one, total energy must keep its initial value and every must remain zero. The square matters: positive and negative violations can cancel in a mean residual, but both contribute positively to its square.
The next chapter adds cutoff and size comparisons. A poorly truncated Hamiltonian can conserve its own energy perfectly. Conservation checks the evolution within the chosen model; convergence checks whether omitted degrees of freedom change the answer.