Walk along the chain
A chain has no sideways direction for the field to spread into. Choose rightward flux as positive. Start with zero flux at the left boundary. Passing a positive charge adds one unit. Neutral sites leave it unchanged. An equal negative charge at the far end brings the flux back to zero.
Label the sites . Write for the flux on the link from site to its right neighbor. At each site, outgoing rightward flux minus incoming rightward flux equals the total charge there.
Fixed sources at the endpoints · zero boundary flux
Intact string
One link screened
Reading: David Tong · Sandbox Physics FR04 finite Hamiltonian
An occupied site need not carry positive charge
Staggered fermions use alternating reference occupations: empty on even sites, occupied on odd sites. Charge is the actual occupation minus this reference. The alternating product configuration is therefore neutral. It is a convenient counting reference; finding the interacting ground state is a separate calculation.
Each actual occupation is zero or one. Relative to the background , filling an even site produces positive charge. Emptying an odd site produces negative charge. The missing particle is called a hole. Moving one particle between those sites can create a positive-negative pair without changing total particle number.
| Configuration | Occupations | Matter charges |
|---|---|---|
| Neutral reference | ||
| Middle particle hops right |
Work through all four sites
Set both boundary fluxes to zero. Put a fixed positive source on site zero and a fixed negative source on site three. Start the matter in its neutral reference configuration. The first source raises the flux to one; the two middle sites leave it unchanged; the final source lowers it to zero. The internal links carry .
Let the middle particle hop right, giving occupations . A negative hole appears on site one and a positive particle on site two. Adding the charges again gives . The new matter charges remove the field from the middle link. This is local screening.
If you changed the occupations but left all three fluxes at one, total charge would still vanish. Two sites would nevertheless fail Gauss’s law. A global test cannot detect where the error occurred.
The boundary restricts the allowed configurations
Sum Gauss’s law over the chain. Every internal flux appears once with each sign and cancels. Right-boundary flux minus left-boundary flux equals total charge. With both boundaries fixed, adding one unbalanced charge must fail the last boundary test.
The same observation gives a useful construction. Start at the left boundary and add each site’s matter charge and external source. This determines every internal flux. Check the right boundary at the end, then check whether each flux lies inside the retained electric range. The next chapter uses this construction to build a smaller physical state space.