The tension of a cosmic string is its energy per unit length, and for the simplest strings it equals its mass per unit length times the square of the speed of light. Multiplied by Newton's constant it becomes one dimensionless number, Gμ/c2, which sets every gravitational effect of the string: how strongly a loop radiates, how long it lives and how loud the background of all loops is. This chapter turns that number into kilograms per metre, connects it to the energy scale at which the string formed, and shows how a network of strings keeps a fixed share of the cosmic energy by chopping off loops.
You need powers of ten, the idea of a density and the Hubble rate H, the fractional rate at which the universe expands. From the next section on we use units with c=1, so the number is written simply as Gμ.
Mass per length and tension
A Nambu–Goto string is the idealisation of a string so thin that only its length matters. Its energy per unit length μ and its tension are equal in these units. If the string came from a field theory, μ is about η2, where η is the energy scale of the transition that made it, and its width is about 1/η, far smaller than any scale we care about here. Auclair et al., 2020, Section 1
To restore units, divide the dimensionless number by G/c2:
Worked example: how heavy is a string with tension ten to the minus tenShow the answer
Put Gμ=10−10 into the formula: μ=1.35×1017kgm−1. The Earth's mass, 5.97×1024kg, would fill 4.4×107m of this string, about 44000km, a little more than the length of the equator.
Why one dimensionless number controls gravity
Every gravitational effect of the string involves Newton's constant together with μ, so the only combination that can appear in a dimensionless result is Gμ. A loop radiates gravitational waves with power ΓGμ2, where the pure number Γ depends on the loop's shape and is about 50 for realistic loops. Dividing by the loop's rest energy μℓ gives a fractional loss rate proportional to Gμ. Auclair et al., 2020, Section 3
The connection to particle physics is
Gμ∼10−6(1016GeVη)2.
A string from a grand-unification scale near 1016GeV has Gμ near 10−6. Measurements of the cosmic microwave background already require Gμ below about 10−7 for several string types. Auclair et al., 2020, eq. 1.1 and Section 1
Worked example: which energy scale gives tension ten to the minus tenShow the answer
Solve the relation for η: η∼1016GeV×10−10/10−6=1014GeV. Each factor of one hundred in Gμ is a factor of ten in the energy scale. The relation is an order-of-magnitude estimate, so keep only one significant figure.
A network that keeps its share of the energy
Long strings stretch across the visible universe and are separated by a typical distance L, defined by ρ∞=μ/L2, where ρ∞ is their energy density. Simulations and the velocity-dependent one-scale model agree that L grows in proportion to cosmic time. Write L=ξt. In the radiation era ξr=0.271 and the root-mean-square string speed is 0.662; in the matter era ξm=0.625. This is called scaling. Auclair et al., 2020, Section 3.1
Scaling means the strings never come to dominate the universe. In the radiation era H=1/(2t), so the critical density is ρc=3H2/(8πG)=3/(32πGt2). The fraction in long strings is
ρcρ∞=ξr2t2μ⋅332πGt2=332πξr2Gμ,
which contains no time at all.
Worked example: the energy share of a string networkShow the answer
With Gμ=10−10 and ξr=0.271, the share is 33.5×10−10/0.0734=4.6×10−8. The same number holds at one second and at ten thousand years: the network grows with the universe without taking it over.
Stretching alone would make the strings longer and their share larger. The network stays in scaling because it keeps cutting string into loops. In the one-scale model the energy put into loops per unit volume and time is c~vˉρ∞/L, with the chopping efficiency c~=0.23 taken from simulations.
Where new loops come from
The simplest model, Model I of Auclair and colleagues, assumes every loop is born with the same fraction of the string separation, ℓ=αLL. In units of cosmic time the birth size is α=αLξ. NANOGrav uses αL≃0.37 and ξr≃0.27, which gives α≃0.10 deep in the radiation era. NANOGrav Collaboration, 2023, Section 5.4, eqs. 43 to 45
Loops then shrink at the steady rate dℓ/dt=−ΓGμ. A loop born at time ti with length αti disappears after
τ=ΓGμαti.
Because the network scales, the number of loops per volume and per length takes the form n(ℓ,t)=t−4n(x) with x=ℓ/t. Within one era, a single function of the ratio x describes the loops at every time. Auclair et al., 2020, eq. 3.1
Lab task
Open the cosmic-string Lab and keep the loop size at its default. Read the lifetime as you move the tension from 10−10 to 10−17, then set the tension to 10−12 and check the value against the formula for τ.
Exercises
Find the mass per length of a string with Gμ=10−12.
A loop with Gμ=10−12 is born with α=0.1. How many times the birth age does it live?
What fraction of the critical density do long strings with Gμ=10−17 hold in the radiation era?
In the one-scale model, what fraction of the long-string energy goes into loops during one unit of cosmic time t in the radiation era?
AnswersShow the answer
μ=10−12×1.347×1027kgm−1=1.35×1015kgm−1, one hundred times lighter than the worked example.
τ/ti=0.1/(50×10−12)=2×109. The Lab reads the same value for this tension.
The share is proportional to Gμ: 4.6×10−8×10−7=4.6×10−15.
The loss rate divided by ρ∞ is c~vˉ/(ξrt)=0.23×0.662/(0.271t)=0.56/t. Over a time t the network turns roughly half its energy into loops, which is why loop production can keep it scaling. The estimate treats the rate as constant over that interval.