One number left over: the cross-ratio
Put four identical operators of dimension at points on a line. Conformal symmetry can move three of them to , and infinity. The fourth then sits at the cross-ratio , a number between and .
After a prefactor fixed by symmetry, the whole correlator is one function . Unlike two- and three-point functions, it is not fixed. It carries information about every operator the theory contains.
Source: D. Mazáč · D. Simmons-Duffin
Two ways to expand the same function
Fusing operators 1 and 2 turns into the identity plus a sum over exchanged primaries. Each term is a squared OPE coefficient times a conformal block, the contribution of one primary and all its descendants. Near a block starts as , so the lightest operators dominate.
Fusing operators 2 and 3 instead gives the same kind of sum in the variable . It converges fastest near . Both expansions describe one function, so where both converge they must agree. That is the crossing equation.
Source: D. Mazáč · D. Simmons-Duffin
Why this is hard to satisfy
Each side is an infinite sum, and the same list of dimensions and coefficients must work on both. Move one dimension a little and the left side changes in one way near while the right side changes in a different way. Other operators would have to shift to compensate, and positivity of limits how they can.
This rigidity is the whole idea of the bootstrap. Instead of computing a theory from a Lagrangian, one asks which lists of operators can satisfy crossing at all.
Source: D. Simmons-Duffin · S. Rychkov
Worked example: checking the free fermion at one point
A one-dimensional free fermion of dimension has the closed form below. At it gives . The exchanged operators have with , , and so on.
Sum the first channel: , so identity plus one operator gives . Adding gives , and the third operator brings it to . Three terms reach six digits.
The crossed channel needs . The closed form gives , but the series converges slowly there: one operator gives , five give , and ten are needed for six digits. Multiplying by returns . The two expansions agree.
Now move the first operator from to and keep everything else. The first channel at falls to and the crossed one rises to . One misplaced operator breaks crossing by about 7 percent.
Source: D. Gaiotto · D. Mazáč