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Sandbox Physics
Searching for axions with cosmic magnetic fields

Mixing in a cluster magnetic field and plasma

Sandbox Physics · · L2 · Course chapter

Whether a cluster converts X-ray photons efficiently comes down to one comparison: is the photon energy above or below a critical energy set by the plasma, the axion mass, the coupling and the field? Above it the mixing wins and conversion is large and nearly independent of energy. Below it the mismatch between photon and axion wins, and the largest possible conversion falls as the square of the energy. When the axion mass equals the plasma frequency, the mismatch vanishes and the energy dependence disappears altogether.

The previous chapter, Photon and axion as two mixing states, derived the two-state probability. This chapter puts cluster numbers into it.

The plasma frequency of intracluster gas

Free electrons respond to a passing wave and shift its dispersion. For X-rays far above the plasma frequency the photon behaves as if it had mass ωpl\omega_{\rm pl}, with

ωpl2=4πα neme.\omega_{\rm pl}^2=\frac{4\pi\alpha\,n_e}{m_e}.

Here nen_e is the electron number density, mem_e the electron mass and α\alpha the fine-structure constant. Evaluated with CODATA constants,

ωpl=3.713×10−11 eV ne1 cm−3.\omega_{\rm pl}=3.713\times10^{-11}\,\mathrm{eV}\,\sqrt{\frac{n_e}{1\,\mathrm{cm^{-3}}}}.

Meyer, Horns and Raue, 2013 print 3.69×10−113.69\times10^{-11} for the coefficient. Ours is 0.6 percent larger. We kept the value computed from the constants and recorded the difference instead of matching the rounded one.

Cluster gas has densities of roughly 10−310^{-3} to 10−1 cm−310^{-1}\,\mathrm{cm^{-3}}, so ωpl\omega_{\rm pl} is a few times 10−1210^{-12} eV. At ne=10−2.5 cm−3n_e=10^{-2.5}\,\mathrm{cm^{-3}} it is 2.09×10−122.09\times10^{-12} eV, and the photon term at 1 keV is Δpl=−0.341 kpc−1\Delta_{\rm pl}=-0.341\,\mathrm{kpc^{-1}}. It scales as density over energy.

One ratio decides the regime

The amplitude factor from the two-state formula can be rewritten with a single ratio. The mismatch is Δpl−Δa=(ma2−ωpl2)/(2E)\Delta_{\rm pl}-\Delta_a=(m_a^2-\omega_{\rm pl}^2)/(2E) and twice the mixing is gaγB⊥g_{a\gamma}B_\perp. Their ratio is Ecrit/EE_{\rm crit}/E, with

Ecrit=∣ma2−ωpl2∣2gaγB⊥.E_{\rm crit}=\frac{\lvert m_a^2-\omega_{\rm pl}^2\rvert}{2g_{a\gamma}B_\perp}.

Substituting gives an exact form for the largest possible conversion:

(2ΔaγΔosc)2=11+(Ecrit/E)2.\left(\frac{2\Delta_{a\gamma}}{\Delta_{\rm osc}}\right)^2=\frac{1}{1+(E_{\rm crit}/E)^2}.

Far above EcritE_{\rm crit} the factor approaches one. Far below it, it falls as (E/Ecrit)2(E/E_{\rm crit})^2. The same critical energy appears as eq. (6) of Meyer, Horns and Raue, written as 2.52.5 GeV times the mass difference in square nanoelectronvolts, divided by the coupling in units of 10−11 GeV−110^{-11}\,\mathrm{GeV^{-1}} and the field in microgauss. Recomputing their prefactor from the constants gives 2.56 GeV, so their 2.5 is a rounded value.

Three cases from the Lab presets

Default tangled field. With gaγ=10−11.5 GeV−1g_{a\gamma}=10^{-11.5}\,\mathrm{GeV^{-1}}, B⊥=5 μGB_\perp=5\,\mu\mathrm G, ne=10−2.5 cm−3n_e=10^{-2.5}\,\mathrm{cm^{-3}} and ma=10−13m_a=10^{-13} eV, the axion mass is negligible next to the plasma frequency. The formula gives Ecrit=7.04E_{\rm crit}=7.04 keV. Meyer's rounded prefactor gives 6.88 keV, a 2 percent difference that comes entirely from the rounding. Across the 1 to 9 keV band the amplitude factor climbs from about 0.02 to above 0.6, so conversion grows with energy.

Mass matches the plasma. Set ma=ωpl=2.09×10−12m_a=\omega_{\rm pl}=2.09\times10^{-12} eV. The diagonal entries are equal, the amplitude factor is one at every energy and Δosc=2Δaγ\Delta_{\rm osc}=2\Delta_{a\gamma}. With gaγ=10−12 GeV−1g_{a\gamma}=10^{-12}\,\mathrm{GeV^{-1}}, B⊥=5 μGB_\perp=5\,\mu\mathrm G and a uniform 96 kpc path,

ΔaγL=7.64×10−3×96=0.733,Pγ→a=sin⁡2(0.733)=0.448.\Delta_{a\gamma}L=7.64\times10^{-3}\times96=0.733,\qquad P_{\gamma\to a}=\sin^2(0.733)=0.448.

Unpolarized survival is 0.776, the same at 0.5 keV as at 10 keV. In a real cluster the density changes along the path, so a resonance like this would hold only in a thin shell where ωpl\omega_{\rm pl} happens to equal mam_a.

Heavier axion. Raise the mass to 10−1110^{-11} eV with gaγ=10−11 GeV−1g_{a\gamma}=10^{-11}\,\mathrm{GeV^{-1}}. Now the axion term dominates and Ecrit=49.0E_{\rm crit}=49.0 keV. The amplitude factor is 4.2×10−44.2\times10^{-4} at 1 keV and 1.7×10−21.7\times10^{-2} at 6.5 keV, a forty-fold rise. The spectrum is untouched at low energy and dips at high energy. A low-energy cutoff of this kind is how X-ray searches lose sensitivity as the mass grows.

The Perseus profile at the published limit

Reynolds and colleagues describe the Perseus electron density with a two-component profile from earlier X-ray work, their eq. (2):

ne(r)=3.9×10−2[1+(r/80 kpc)2]1.8+4.05×10−3[1+(r/280 kpc)2]0.87 cm−3.n_e(r)=\frac{3.9\times10^{-2}}{[1+(r/80\,\mathrm{kpc})^2]^{1.8}}+\frac{4.05\times10^{-3}}{[1+(r/280\,\mathrm{kpc})^2]^{0.87}}\,\mathrm{cm^{-3}}.

In their field model B the magnetic pressure is a fixed fraction of the gas pressure, the field is about 7.5 microgauss at 25 kpc, and treating the cluster as isothermal makes the field fall as the square root of the density. Reynolds et al., 2020 Leave out their random cell structure and evaluate only that radial scaling at the coupling they exclude, gaγ=7.9×10−13 GeV−1g_{a\gamma}=7.9\times10^{-13}\,\mathrm{GeV^{-1}}:

Table 3.1 Critical energy along the model-B radial profile, for a very light axion.
RadiusElectron densityFieldCritical energy
25 kpc3.70×10−2 cm−33.70\times10^{-2}\,\mathrm{cm^{-3}}7.5 μG7.5\,\mu\mathrm G220 keV
100 kpc1.08×10−2 cm−31.08\times10^{-2}\,\mathrm{cm^{-3}}4.1 μG4.1\,\mu\mathrm G119 keV
200 kpc3.93×10−3 cm−33.93\times10^{-3}\,\mathrm{cm^{-3}}2.4 μG2.4\,\mu\mathrm G72 keV

Every critical energy sits far above the Chandra band. At this coupling Perseus mixes X-rays only weakly: a single coherent cell converts well under one percent. A percent-level signal builds up only because the photons cross many cells. At 5 keV the oscillation length runs from about 8 kpc near the centre to about 74 kpc at 200 kpc, close to the cell sizes, so each cell's contribution changes phase with energy. That is where the ripples come from.

The Lab does not apply a telescope's energy resolution. Ripples narrower than the instrument resolution would be partly smoothed in a real spectrum, and a real analysis has to pass the model through the instrument response.

Lab tasks

  1. Predict. On the default preset, open the advanced panel and read the critical energy. Say whether a 2 keV photon or an 8 keV photon converts more on average.
  2. Change one condition. Raise the density slider by one decade. Predict how the critical energy changes, then check.
  3. Compare. Choose the plasma-resonance preset and drag the energy cursor across the whole band. The solid curve should stay flat.
  4. Explain. Choose the heavier-axion preset. Find roughly where the dashed mean first drops below 0.95. It happens near 3.6 keV. Explain why this is more than ten times below the critical energy: each of the 24 cells adds a small conversion, and the small amounts accumulate.

Exercises

  1. A cluster has ne=10−3 cm−3n_e=10^{-3}\,\mathrm{cm^{-3}} and B⊥=2 μGB_\perp=2\,\mu\mathrm G. For a very light axion and gaγ=10−12 GeV−1g_{a\gamma}=10^{-12}\,\mathrm{GeV^{-1}}, estimate EcritE_{\rm crit}.
  2. At fixed coupling and field, how does EcritE_{\rm crit} change if the density doubles? If instead the axion mass rises well above the plasma frequency and then doubles?
  3. Why does the resonant case lose its energy dependence even though Δpl\Delta_{\rm pl} itself still depends on energy?
Answers
  1. ωpl=3.713×10−11×10−3=1.17×10−12\omega_{\rm pl}=3.713\times10^{-11}\times\sqrt{10^{-3}}=1.17\times10^{-12} eV, so ωpl2=1.38×10−24 eV2\omega_{\rm pl}^2=1.38\times10^{-24}\,\mathrm{eV^2}. With 2gaγB⊥=2×10−21×3.91×10−8=7.81×10−29 eV2g_{a\gamma}B_\perp=2\times10^{-21}\times3.91\times10^{-8}=7.81\times10^{-29}\,\mathrm{eV}, the critical energy is 1.77×1041.77\times10^{4} eV, about 18 keV.
  2. The critical energy is proportional to ωpl2\omega_{\rm pl}^2, which is proportional to density, so doubling the density doubles it. When the mass dominates, it scales as ma2m_a^2, so doubling the mass quadruples it.
  3. Only the difference Δpl−Δa\Delta_{\rm pl}-\Delta_a enters the probability. Both terms scale as one over energy, so when ma=ωplm_a=\omega_{\rm pl} they cancel at every energy, and the mixing term gaγB⊥/2g_{a\gamma}B_\perp/2 has no energy in it.

Try it in the Lab: Compare Mass matches the plasma with Heavier axion, low-energy cutoff, and read the critical energy in the advanced panel.

Sources

  1. Meyer, Horns and Raue, 2013
  2. Reynolds et al., 2020

Keep reading

What this page links to directly

Searching for axions with cosmic magnetic fields · Reading path

From two mixing states to a published limit

  1. ArticleHow could an invisible particle change a distant spectrum?
  2. ArticlePhoton and axion as two mixing states
  3. You are hereMixing in a cluster magnetic field and plasma
  4. ArticleRandom domains, polarization and stellar cooling
  5. ArticleRecompute a cluster sightline from saved inputs
  6. ArticleReading the Chandra NGC 1275 axion limit
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