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Acoustics and ultrasound

L3 · Chapter 5

How acoustic radiation force pushes beads to the nodes of a standing wave

Over one period the sound pressure is positive half the time and negative the other half, so it averages to zero. Yet beads are pushed firmly to the middle of the channel. The reason is a second-order effect: the particle scatters the sound, and the product of the scattered and incident waves leaves a nonzero average force. This chapter writes that force as a potential and asks where its valley lies, how deep it is and how stiff.

How a field that averages to zero leaves a force

The first-order fields p1p_1 and v1\mathbf v_1 average to zero over a period. A particle whose density and compressibility differ from water’s scatters the incident wave, though, and the product of incident and scattered fields is second order. Its time average is not zero: that is the acoustic radiation force.

When the particle is much smaller than the wavelength (ka≪1ka\ll1) the force is minus the gradient of a potential with two terms. A particle stiffer than water has higher energy where the pressure swings strongly (the monopole term, coefficient f1f_1). A particle denser than water has lower energy where the liquid sloshes strongly (the dipole term, coefficient f2f_2).

U=4π3a3[f1κ02⟨p12⟩−f234ρ0⟨v12⟩],F=−∇UU=\frac{4\pi}{3}a^3\left[f_1\frac{\kappa_0}{2}\langle p_1^2\rangle-f_2\frac{3}{4}\rho_0\langle v_1^2\rangle\right],\qquad \mathbf F=-\nabla U
Settnes and Bruus, Eqs. 48a–b. aa is the particle radius and angle brackets denote time averages.
f1=1−κpκ0,f2=2(ρ~−1)2ρ~+1,ρ~=ρpρ0f_1=1-\frac{\kappa_p}{\kappa_0},\qquad f_2=\frac{2(\tilde\rho-1)}{2\tilde\rho+1},\quad \tilde\rho=\frac{\rho_p}{\rho_0}
This is the form without viscosity. With the viscous boundary layer, f2f_2 becomes the complex expression of Eqs. 48d–e, of which the real part is taken.

Source: M. Settnes and H. Bruus · R. Barnkob

Force and contrast factor in a one-dimensional standing wave

Insert the standing wave of Chapter 3 into the potential and the two terms combine into a sinusoidal force. All the material properties fold into one number, the acoustic contrast factor Φ\Phi, whose sign decides where the particle goes.

Particles with Φ>0\Phi>0 are pushed to pressure nodes: polystyrene beads have Φ=0.165\Phi=0.165, Pyrex beads about 0.54, and a cell with the parameters tabulated by Settnes and Bruus about 0.068. Particles with Φ<0\Phi<0, more compressible than water or much lighter, are pushed to pressure antinodes; in an n=1n=1 channel those are the side walls.

Fy=4πΦ ka3Eacsin⁡(2ky),Φ=f13+f22F_y=4\pi\Phi\,ka^3E_{\mathrm{ac}}\sin(2ky),\qquad \Phi=\frac{f_1}{3}+\frac{f_2}{2}
Eq. 2 of Barnkob and co-workers with the origin at the left wall. The force scales with a3a^3, the particle volume.

Source: R. Barnkob · M. Settnes and H. Bruus

Stable point, stiffness and return time

The force vanishes where sin⁡(2ky)=0\sin(2ky)=0. Only zeros where the force has a negative slope are stable: a particle displaced to the right is pushed back left. For Φ>0\Phi>0 this needs cos⁡(2ky)<0\cos(2ky)<0, which is exactly a pressure node; the same point is unstable for Φ<0\Phi<0. Near the stable point the force grows in proportion to the displacement, like a spring.

A bead in water is so small and slow that its inertia dies out within tens of microseconds, and the motion is overdamped: the radiation force balances the Stokes drag 6πηa6\pi\eta a. On the centre plane this equation can be solved exactly, with no numerical integration. The experiment uses that solution as an independent reference for the integrator’s release curve, and the two agree to better than 4×10−13 m4\times10^{-13}\,\mathrm{m}.

κtrap=8π∣Φ∣k2a3Eac,τ=6πηaκtrap\kappa_{\mathrm{trap}}=8\pi|\Phi|k^2a^3E_{\mathrm{ac}},\qquad \tau=\frac{6\pi\eta a}{\kappa_{\mathrm{trap}}}
The stiffness is the magnitude of the force slope at the stable point, and τ\tau is the time constant with which a small displacement decays.
y˙=Asin⁡(2ky)  ⇒  tan⁡(ky)=tan⁡(ky0) e2kAt,A=2Φka2Eac3η\dot y=A\sin(2ky)\;\Rightarrow\;\tan(ky)=\tan(ky_0)\,e^{2kAt},\qquad A=\frac{2\Phi ka^2E_{\mathrm{ac}}}{3\eta}
Separate the variables and integrate. AA is the amplitude of the radiation drift speed; streaming on the centre plane has the same sinusoidal shape, so including it only adds to AA.
pressurevelocitypressure nodehard wall
Half-wave resonance across a channel with hard side walls. Teal: pressure amplitude, largest at the walls and zero at the centre. Amber: velocity amplitude, zero at the walls and largest at the centre. Beads with Φ>0\Phi>0 collect on the pressure node. Original schematic.

Source: R. Barnkob · M. Settnes and H. Bruus

Worked example: a 5 µm polystyrene bead

The experiment’s defaults: a channel w=377 μmw=377\,\mu\mathrm{m} wide at n=1n=1, so k=π/w=8.33×103 m−1k=\pi/w=8.33\times10^3\,\mathrm{m^{-1}}; Eac=20 J/m3E_{\mathrm{ac}}=20\,\mathrm{J/m^3}; a polystyrene bead 5 µm across with Φ=0.165\Phi=0.165; water viscosity η=0.890 mPa s\eta=0.890\,\mathrm{mPa\,s}.

The largest radiation force is 4πΦka3Eac=5.40 pN4\pi\Phi ka^3E_{\mathrm{ac}}=5.40\,\mathrm{pN}, halfway between the node and a wall. Dividing by the Stokes coefficient 6πηa=4.19×10−8 N s/m6\pi\eta a=4.19\times10^{-8}\,\mathrm{N\,s/m} gives a top drift speed of 129 µm/s.

The stable point is the channel centre. The stiffness is κtrap=9.00×10−8 N/m\kappa_{\mathrm{trap}}=9.00\times10^{-8}\,\mathrm{N/m} and the return time constant τ=0.466 s\tau=0.466\,\mathrm{s}, the value the experiment shows. Released from y0=w/8y_0=w/8, the closed-form solution of the drift equation takes 1.45 s to bring the bead within 10 µm of the node (with streaming included).

The well depth is Fmax⁡/k=6.5×10−16 JF_{\max}/k=6.5\times10^{-16}\,\mathrm{J}, about 1.6×1051.6\times10^5 times the thermal energy at room temperature, and thermal motion jiggles the bead about the node by about 0.21 µm root mean square. The experiment leaves out Brownian motion, which is negligible for a bead this size and matters for sub-micrometre particles.

Source: R. Barnkob · M. Settnes and H. Bruus

Try it in the Lab

Drag a bead and watch it return to the node

  1. In the default preset, drag the probe bead to a quarter of the way across the channel and let go. Compare the simulated curve with the exact solution in the “Probe return after release” chart.
  2. Turn off “Include acoustic streaming” and repeat. How much does the return time change?
  3. Choose “Soft particles flee to the walls” and see where the particles go once the contrast factor is negative. Drag one to the channel centre and let go: does it stay?

Exercises with explained answers

  1. In the same field, what are the largest radiation force and the return time for a 5 µm Pyrex bead?

    Show the answer

    With the viscous correction Φ=0.562\Phi=0.562 (0.539 without it), so the largest force is 5.40×0.562/0.165=18.4 pN5.40\times0.562/0.165=18.4\,\mathrm{pN} and the return time 0.466×0.165/0.562=0.137 s0.466\times0.165/0.562=0.137\,\mathrm{s}, 3.4 times faster.

  2. Halve the bead diameter to 2.5 µm. What is the return time now, and why?

    Show the answer

    The force scales with a3a^3 and the drag with aa, so the drift speed scales with a2a^2 and the time constant grows four times, to about 1.86 s. Small particles are hard to focus, which is why streaming starts to win in the next chapter.

  3. Why can a particle with Φ<0\Phi<0 not rest at a pressure node?

    Show the answer

    At the node cos⁡(2ky)=−1\cos(2ky)=-1, and the force slope 8πΦk2a3Eaccos⁡(2ky)8\pi\Phi k^2a^3E_{\mathrm{ac}}\cos(2ky) is positive when Φ<0\Phi<0: a particle nudged right is pushed further right. It slides to the pressure antinodes, where the slope is negative; in an n=1n=1 channel those are the two side walls.

Sources and what we recomputed

  1. R. Barnkob, P. Augustsson, T. Laurell and H. Bruus, Acoustic radiation- and streaming-induced microparticle velocities determined by micro-PIV in an ultrasound symmetry plane, arXiv:1208.6534v1; Physical Review E 86, 056307 (2012)

    Version 1, 31 August 2012, read in full. Eq. 1 (standing-wave field), Eq. 2 (radiation force), Eqs. 5–7 (streaming scale and Rayleigh streaming), Eqs. 9–10 (geometry and thermoviscous corrections), Eqs. 12–14 (velocity amplitude, velocity ratio, critical diameter), Eqs. 16–18 and Table I (wall drag), Table II (material data), Tables IV–V and Figs. 8–9 (measured energy densities, streaming coefficients and velocity ratios). We recompute the theory values; the measured data are quoted, not reproduced.

  2. M. Settnes and H. Bruus, Forces acting on a small particle in an acoustical field in a viscous fluid, arXiv:1110.6037v1; Physical Review E 85, 016327 (2012)

    Version 1, 27 October 2011, read in full. Eq. 1 (viscous penetration depth), Eqs. 4–5 (first-order pressure and compressibility), Eqs. 48a–e (Gor’kov potential with the viscous dipole coefficient) and Table I (Pyrex and cell parameters).

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