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Sandbox Physics

M041 · Work and energy

Work–Energy Graph Studio

Draw the force along a rail, follow exact piecewise motion through turns, then integrate acquired force samples against the independent energy ledger.

Interactive modelWork–Energy Graph Studio
Trajectory windowReady\text{Ready}
Selected timeReady\text{Ready}
Selected positionReady\text{Ready}
Signed velocityReady\text{Ready}
Longitudinal net forceReady\text{Ready}
Net work from launchReady\text{Ready}
Kinetic energyReady\text{Ready}
Potential; zero at rail originReady\text{Ready}
Maximum energy-ledger residualReady\text{Ready}
Reached turnsReady\text{Ready}
Available trajectory durationReady\text{Ready}
Acquired force stationsReady\text{Ready}
Work from acquired forceReady\text{Ready}
Acquired minus reference workReady\text{Ready}

Physics tutorial

Work–Energy Graph Studio

BackgroundA force profile predicts both a time trajectory and a signed spatial integral.

Why it mattersDraw the force along a rail, follow exact piecewise motion through turns, then integrate acquired force samples against the independent energy ledger.

Start with the essentials

Focus question
Does signed force area predict a turn?
One-sentence intuition
Independent motion and force integrals should agree within numerical error.

Core mathematical model

Signed area

W0→x=∫x0xF(ξ) dξW_{0\to x}=\int_{x_0}^{x}F(\xi)\,\mathrm d\xi

Work changes sign with displacement and force; returning is not accumulated absolute area.

Independent time-domain motion

mx¨=F(x)F(x)=Fi+ai(x−xi)xi=i m\begin{aligned}m\ddot x&=F(x)\\F(x)&=F_i+a_i(x-x_i)\\x_i&=i\,\mathrm m\end{aligned}

Each segment has a constant, trigonometric or hyperbolic solution; turns and knot crossings restart it.

A separate ledger

K=12mv2U(x)=−∫0xF(ξ) dξΔK−W=0\begin{aligned}K&=\tfrac12m v^2\\U(x)&=-\int_0^x F(\xi)\,\mathrm d\xi\\\Delta K-W&=0\end{aligned}

Potential is referenced to the rail origin. The ledger checks the time solution against an independently integrated force.

Only acquired force enters the estimate

W^=∑iFiobs+Fi+1obs2 (xi+1−xi)\widehat W=\sum_i\frac{F_i^{\mathrm{obs}}+F_{i+1}^{\mathrm{obs}}}{2}\,(x_{i+1}-x_i)

The estimator interpolates measured force for partial intervals; it never receives true kinetic energy.

Common difficulties

Model and evidence

Typical misconceptionEvery zero-speed point is a stop, and a smooth data curve is exact.

Better mental modelInspect the force at rest and the event history; sparse force data can miss knots.

Run the experiment

  1. 01

    Draw a force profile

    Drag blue force knots; vary the initial velocity and mass.

    What to observe: The same signed force drives the 3D cart and its work integral.
  2. 02

    Find a real turn

    Compare Harmonic turns, Barrier and return, and Initial reverse motion.

    What to observe: Velocity passes through zero with a nonzero restoring force; work unwinds on return.
  3. 03

    Separate rest from asymptotic approach

    Compare Equilibrium with Asymptotic approach.

    What to observe: Zero speed at zero force is equilibrium; the critical unstable state is approached without crossing.
  4. 04

    Measure the area

    Acquire with a scan that includes force knots, then use a sparse scan and add noise.

    What to observe: The data estimator cannot recover force detail that was not sampled.