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Sandbox Physics

Spatial mechanisms · Uneven rotation

Universal Joint

Follow two intersecting shafts joined by a gold right-angle cross. Increase the bend, compare input and output phase markers, and measure the speed ripple hidden inside a complete revolution.

Interactive modelUniversal Joint
Output angle00
Output / input speed00
Output phase error00
Output acceleration00
Required input torque00
Signed load power00
Cross orthogonality residual00
Quasistatic power residual00

Physics tutorial

A complete turn can hide uneven speed

BackgroundCouplings carry rotation between shafts whose axes do not coincide.

Why it mattersWatch the connecting geometry before reading the speed curve.

Start with the essentials

Focus question
Why does a bent universal joint change output speed twice each turn?
One-sentence intuition
The right-angle cross constrains the two fork orientations, so equal angle increments cannot pass through unchanged.

Core mathematical model

Right-angle cross constraint

tan⁡ϕ=cos⁡βtan⁡θ,ϕ=unwrap⁡ ⁣[atan2⁡(cos⁡βsin⁡θ,cos⁡θ)]\tan\phi=\cos\beta\tan\theta,\qquad\phi=\operatorname{unwrap}\!\left[\operatorname{atan2}(\cos\beta\sin\theta,\cos\theta)\right]

Quadrant-safe unwrapping preserves a full output turn; the tangent relation alone loses quadrant information.

Instantaneous speed ratio

R=ϕ˙ω=cos⁡β1−sin⁡2βsin⁡2θ,Rmin⁡=cos⁡β,Rmax⁡=1cos⁡βR=\frac{\dot\phi}{\omega}=\frac{\cos\beta}{1-\sin^2\beta\sin^2\theta},\quad R_{\min}=\cos\beta,\quad R_{\max}=\frac1{\cos\beta}

The extrema occur a quarter input turn apart and the pattern repeats each half-turn.

Output acceleration

ϕ¨=ω2cos⁡βsin⁡2βsin⁡2θ(1−sin⁡2βsin⁡2θ)2\ddot\phi=\omega^2\frac{\cos\beta\sin^2\beta\sin2\theta}{(1-\sin^2\beta\sin^2\theta)^2}

Input angular speed is fixed; output angular acceleration can still be nonzero.

Massless quasistatic virtual power

τin=−τodϕdθ,τinω+τoϕ˙=0\tau_{\rm in}=-\tau_o\frac{\mathrm d\phi}{\mathrm d\theta},\qquad\tau_{\rm in}\omega+\tau_o\dot\phi=0

No frictional loss or inertial power is included.

Common difficulties

Equal turns versus equal speed

Typical misconceptionOne output turn per input turn guarantees constant speed.

Better mental modelA universal joint has a varying instantaneous ratio; an ideal parallel Oldham coupling has a constant ratio.

Kinematics versus dynamics

Typical misconceptionA smooth animation establishes acceptable bearing loads and wear.

Better mental modelInput motion is prescribed, and the connecting parts are massless and frictionless. Dynamic inertia, real clearances and contact forces require a different model.

Run the experiment

  1. 01

    Establish the aligned limit

    Select aligned shafts and play one turn.

    What to observe: Both shaft phase markers agree and the speed ratio stays unity.
  2. 02

    Increase the bend

    Compare the slowest and fastest output presets, then inspect the cross from different views.

    What to observe: The output speed oscillates twice while the orthogonality residual remains near numerical precision.
  3. 03

    Inspect the transfer of power

    Reverse the signed load and export the cycle.

    What to observe: Torque and power change sign; the prescribed motion does not.

Theory & apparatus: Carnegie Mellon · Universal Joint · Ruland · Oldham Coupling

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