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Sandbox Physics

M019 · Forces & measurement

Terminal Fall & Drag Laws

Drop equal-area bodies with different masses, compare linear and quadratic resistance, start above terminal speed and infer drag from a sampled speed record.

Interactive modelTerminal Fall & Drag Laws
Measurement stateReady\text{Ready}
Selected timeReady\text{Ready}
Model downward speed AReady\text{Ready}
Model downward speed BReady\text{Ready}
Reference terminal speed AReady\text{Ready}
Reference terminal speed BReady\text{Ready}
Terminal speed ratioReady\text{Ready}
Upward drag on AReady\text{Ready}
Downward acceleration AReady\text{Ready}
Raw-fit linear coefficientReady\text{Ready}
Raw-fit quadratic coefficientReady\text{Ready}
Linear force residual RMSReady\text{Ready}
Quadratic force residual RMSReady\text{Ready}
Usable inferred force pointsReady\text{Ready}
Full-run sampled work residual AReady\text{Ready}
Recorded sensor rowsReady\text{Ready}

Physics tutorial

Terminal Fall & Drag Laws

BackgroundGravity and velocity-dependent resistance produce distinct mass scaling and relaxation.

Why it mattersDrop equal-area bodies with different masses, compare linear and quadratic resistance, start above terminal speed and infer drag from a sampled speed record.

Start with the essentials

Focus question
Can two falling masses reveal the drag law?
One-sentence intuition
At terminal speed the forces balance; a superterminal release slows down.

Core mathematical model

Downward speed convention

mu˙=mg−D(u),u=−y˙≥0m\dot u=mg-D(u),\qquad u=-\dot y\geq0

Both models oppose the downward velocity; overspeed can produce negative downward acceleration.

Alternative force laws

D1=bu,uT,1=mg/bD2=cu2,c=ρCDA/2uT,2=mg/c\begin{aligned}D_1&=bu,\quad u_{T,1}=mg/b\\D_2&=cu^2,\quad c=\rho C_D A/2\\u_{T,2}&=\sqrt{mg/c}\end{aligned}

The linear coefficient is independent; the quadratic coefficient is constant in this model.

Independent raw-data inference

D^i=m(g−u˙^i)\widehat D_i=m\left(g-\widehat{\dot u}_i\right)

A local speed slope uses raw times and speeds, without consulting the reference trajectory.

Work and energy

Δ(K+U)=−∫0TD(u)u dt\Delta(K+U)=-\int_0^T D(u)u\,\mathrm dt

The separately sampled integral retains its finite-spacing error.

Common difficulties

Read the force correctly

Typical misconceptionA terminal-speed trace uniquely determines the whole drag law.

Better mental modelA short plateau may fit several laws. Mass scaling and a wide transient help, while speed noise, derivative windows and constant-coefficient assumptions can bias the inferred coefficients.

Run the experiment

  1. 01

    Compare mass scaling

    Switch between linear, quadratic and vacuum at the same mass ratio.

    What to observe: Terminal speeds scale differently; vacuum accelerations coincide.
  2. 02

    Start above equilibrium

    Choose Above terminal speed, then scrub the gold clock.

    What to observe: Drag exceeds weight and downward speed decreases.
  3. 03

    Acquire before inferring

    Acquire a broad transient and compare both fitted residuals.

    What to observe: The force scatter comes from differentiated recorded speeds.
  4. 04

    Challenge the estimate

    Choose Noisy differentiation and widen the derivative window.

    What to observe: Noise decreases, but transient smoothing introduces bias.