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Sandbox Physics

M019 · Forces & measurement

Terminal Fall & Drag Laws

Can two falling masses reveal the drag law? Yes. Drop two bodies of the same size and shape but different masses; each settles at the speed where drag balances its weight. If drag grows in proportion to speed, doubling the mass doubles that speed. If drag grows with speed squared, the speed rises only by about 1.4 times.

Drop two bodies with the same cross-sectional area but different masses. Compare linear and quadratic drag, start a fall above terminal speed and estimate the drag from a sampled speed record.

Interactive modelTerminal Fall & Drag Laws
Measurement stateReady\text{Ready}
Selected timeReady\text{Ready}
Model downward speed AReady\text{Ready}
Model downward speed BReady\text{Ready}
Reference terminal speed AReady\text{Ready}
Reference terminal speed BReady\text{Ready}
Terminal speed ratioReady\text{Ready}
Upward drag on AReady\text{Ready}
Downward acceleration AReady\text{Ready}
Raw-fit linear coefficientReady\text{Ready}
Raw-fit quadratic coefficientReady\text{Ready}
Linear force residual RMSReady\text{Ready}
Quadratic force residual RMSReady\text{Ready}
Usable inferred force pointsReady\text{Ready}
Full-run sampled work residual AReady\text{Ready}
Recorded sensor rowsReady\text{Ready}

Physics tutorial

Terminal Fall & Drag Laws

BackgroundGravity pulls down, and the resistance grows with speed. Each drag law gives terminal speed its own dependence on mass and its own way of approaching that speed.

Why it mattersDrop two bodies with equal area and different masses, compare linear and quadratic drag and start a fall above terminal speed. Then try to infer the drag from a sampled speed record.

Start with the essentials

Focus question
Can two falling masses reveal the drag law?
One-sentence intuition
At terminal speed the forces balance; a body released faster than that slows down.

Core mathematical model

Equation of motion with downward speed positive

mu˙=mg−D(u),u=−y˙≥0m\dot u=mg-D(u),\qquad u=-\dot y\geq0

Both drag laws oppose the downward velocity. A body falling faster than terminal speed can have a negative downward acceleration.

Two drag laws to compare

D1=bu,uT,1=mg/bD2=cu2,c=ρCDA/2uT,2=mg/c\begin{aligned}D_1&=bu,\quad u_{T,1}=mg/b\\D_2&=cu^2,\quad c=\rho C_D A/2\\u_{T,2}&=\sqrt{mg/c}\end{aligned}

The linear coefficient is set independently. The quadratic coefficient is constant in this model.

Drag inferred from raw data

D^i=m(g−u˙^i)\widehat D_i=m\left(g-\widehat{\dot u}_i\right)

The local slope of speed comes from the raw times and speeds only. The reference trajectory is never used.

Work and energy

Δ(K+U)=−∫0TD(u)u dt\Delta(K+U)=-\int_0^T D(u)u\,\mathrm dt

This integral is sampled separately, so it keeps the error that comes from its finite spacing.

Common difficulties

One plateau does not fix the drag law

Typical misconceptionOnce I see the terminal speed, I know the whole drag law.

Better mental modelA short plateau may fit several laws. Comparing two masses and recording a wide transient help. Speed noise, the derivative window and the assumption of a constant coefficient can all bias the inferred coefficients.

Run the experiment

  1. 01

    Compare how mass matters

    Switch between linear, quadratic and vacuum at the same mass ratio.

    What to observe: Terminal speed depends on mass differently under each law. In vacuum, both bodies have the same acceleration.
  2. 02

    Start faster than terminal speed

    Choose Above terminal speed, then drag a sphere to replay its fall.

    What to observe: Drag is larger than the weight, so the downward speed decreases.
  3. 03

    Record data before fitting

    Acquire a broad transient and compare the residuals of both fits.

    What to observe: The scatter in force comes from differentiating the recorded speeds.
  4. 04

    Test the estimate

    Choose Noisy differentiation and widen the derivative window.

    What to observe: The noise drops, but smoothing over the transient biases the result.
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