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Drawing mechanisms · Geometric inversion

Peaucellier Inversor

How can hinged bars draw a straight line without a guide? By geometric inversion. The rhombus and the two long bars keep the pen and the input point on one line through the fixed pivot, and the product of their distances from that pivot stays fixed. Inversion turns a circle through the pivot into a straight line. So when the crank's circle passes through that pivot, the pen draws an exact straight line; any other crank length gives a circular arc.

Swing the crank around its circle and watch a hinged rhombus steer the pen along a straight line. Change the input circle to bend the path, look closely at the stacked pivots, and check the geometric invariant behind the drawing.

Interactive modelPeaucellier Inversor
Pen horizontal position00
Pen vertical position00
Pen speed00
Pen acceleration magnitude00
Inversion distance product00
Straight-reference deviation00
Local path curvature00
Largest constraint residual00

Physics tutorial

A straight path made entirely of hinges

BackgroundThe links and joints of a mechanism can build a geometric construction into its motion.

Why it mattersFollow the pen first, then check the rods that hold it on its path.

Start with the essentials

Focus question
What must be true of the input circle for the output to be straight?
One-sentence intuition
The rhombus keeps the input point and the pen on one line through the fixed pivot, and the product of their distances from that pivot stays constant.

Core mathematical model

Geometric inversion

K=ℓ2−r2,Q=KP∣P∣2K=\ell^2-r^2,\quad\mathbf Q=\frac{K\mathbf P}{|\mathbf P|^2}

The fixed pivot is the origin. The two long links and the four equal sides of the rhombus enforce this relation.

The input circle

P=(D+Rcos⁡θ,Rsin⁡θ)\mathbf P=(D+R\cos\theta,R\sin\theta)

Its center is the other fixed pivot. When the radius equals the distance between the pivots, the circle passes through the origin.

When the path is exactly straight

R=D⟹Qx=K2D,Qy=K2Dtan⁡θ2R=D\quad\Longrightarrow\quad Q_x=\frac K{2D},\quad Q_y=\frac K{2D}\tan\frac\theta2

Only a safe arc of crank angles is shown. Driving the crank through the inversion center leads to a singular position.

The output circle in general

(D2−R2)∣Q∣2−2KDQx+K2=0(D^2-R^2)|\mathbf Q|^2-2KDQ_x+K^2=0

When the coefficient of the quadratic term vanishes, the same equation describes a line.

Common difficulties

The pale curve is not a measurement

Typical misconceptionThe pale curve is an independent experimental check.

Better mental modelIt is the full path of the ideal model. The constraint residuals and independent geometric tests check that the model is consistent; no real data are acquired.

The motion is set directly

Typical misconceptionA smooth trace proves that a real mechanism can be driven safely at this rate.

Better mental modelMass, friction, contact forces, clearances and drive dynamics need a separate analysis. The thicknesses of the three-dimensional parts only show how the pieces are assembled.

Run the experiment

  1. 01

    Trace the default path

    Use the drawing-plane view, then play or drag the coral handle.

    What to observe: Every bar keeps its length, and the pen, with no guide of its own, moves along a vertical line.
  2. 02

    Bend the straight path

    Change the crank radius ratio, keeping the two fixed pivots in place.

    What to observe: The pen now follows a circular arc, although the inversion product is still constant.
  3. 03

    Separate geometry from speed

    Increase the angular rate and export the phase sweep.

    What to observe: The pen covers the same path faster. Velocities grow in proportion to the angular rate, and accelerations grow with its square.

Geometry & apparatus: Il Giardino di Archimede · Peaucellier · Caltech · Elliptical Trammel

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