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Sandbox Physics

M043 · Work and energy

Conservative Forces & Path Dependence

Edit two paths between shared endpoints. Separate potential work, rotational circulation and sliding loss; test acquired field-force samples against the geometric loop.

Interactive modelConservative Forces & Path Dependence
Analytic field classificationReady\text{Ready}
First route field workReady\text{Ready}
Second route field workReady\text{Ready}
First route with resistanceReady\text{Ready}
Second route with resistanceReady\text{Ready}
First route lengthReady\text{Ready}
Second route lengthReady\text{Ready}
Closed-loop field workReady\text{Ready}
Closed-loop resistance workReady\text{Ready}
Closed-loop total workReady\text{Ready}
Oriented loop areaReady\text{Ready}
Curl times oriented areaReady\text{Ready}
Length change at double panelsReady\text{Ready}
Selected route potential-part workReady\text{Ready}
Selected tangentReady\text{Ready}
Acquired force stationsReady\text{Ready}
Acquired closed-loop field workReady\text{Ready}
Acquired minus reference loopReady\text{Ready}

Physics tutorial

Conservative Forces & Path Dependence

BackgroundTwo journeys expose the distinction between an endpoint potential and a directed loop.

Why it mattersEdit two paths between shared endpoints. Separate potential work, rotational circulation and sliding loss; test acquired field-force samples against the geometric loop.

Start with the essentials

Focus question
Does the same destination require the same work?
One-sentence intuition
One zero loop does not establish a global potential.

Core mathematical model

Known conservative and rotational parts

F=(−kx−γy, −G−ky+γx)Uc=12k(x2+y2)+Gy\begin{aligned}\mathbf F&=(-kx-\gamma y,\,-G-ky+\gamma x)\\U_c&=\tfrac12k(x^2+y^2)+Gy\end{aligned}

Only the spring and uniform downward parts are generated by this potential.

A path integral projects onto the tangent

WC=∫01F(c(q))⋅c′(q) dqW_C=\int_0^1\mathbf F(\mathbf c(q))\cdot\mathbf c^{\prime}(q)\,\mathrm dq

The path parameter is not time. The apparatus is driven along the selected path.

Oriented loop and curl

Aor=12∮(x dy−y dx)∮F⋅dr=2γAor\begin{aligned}A_{\mathrm{or}}&=\tfrac12\oint(x\,\mathrm dy-y\,\mathrm dx)\\\oint\mathbf F\cdot\mathrm d\mathbf r&=2\gamma A_{\mathrm{or}}\end{aligned}

The first path forward and second backward define orientation. Self-intersections contribute with winding sign.

Dissipation does not reverse sign

Wf=−fLWf,loop=−f(LA+LB)\begin{aligned}W_f&=-fL\\W_{f,\mathrm{loop}}&=-f(L_A+L_B)\end{aligned}

Resistance depends on traversal direction, so its loop work is not a curl integral of one position-only field.

Raw force–displacement estimate

W^C=∑iFiobs+Fi+1obs2⋅(ri+1−ri)\widehat W_C=\sum_i\frac{\mathbf F_i^{\mathrm{obs}}+\mathbf F_{i+1}^{\mathrm{obs}}}{2}\cdot(\mathbf r_{i+1}-\mathbf r_i)

Positions are exact in this simulated acquisition; field-force components carry bounded deterministic noise.

Common difficulties

Model and evidence

Typical misconceptionReversing a loop always reverses every work contribution.

Better mental modelPosition-only field work reverses; sliding resistance follows the new tangent and still dissipates.

Run the experiment

  1. 01

    Keep endpoints fixed

    Edit both internal points on each route.

    What to observe: Potential-part work stays fixed, even when path length changes.
  2. 02

    Give the field circulation

    Choose Rotational field and change its sign.

    What to observe: Closed-loop field work follows oriented area and reverses with the loop.
  3. 03

    Add resistance

    Set sliding resistance, then reverse both routes.

    What to observe: The field term changes sign while the resistance term remains negative.
  4. 04

    Acquire a geometric integral

    Acquire field forces; increase scan intervals and compare with the model.

    What to observe: Measured loop work is a force–displacement sum; resistance is still a separate calculation.