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Sandbox Physics

M026 · Solid mechanics

Column Buckling & Imperfection

Load a pinned rectangular column with controlled crookedness and eccentricity. Compare linear amplification with a separate displacement-controlled elastica branch, then infer the critical load from raw force and lateral readings.

Interactive modelColumn Buckling & Imperfection
Euler critical loadReady\text{Ready}
Applied compressionReady\text{Ready}
Peak lateral offsetReady\text{Ready}
Maximum absolute fibre stressReady\text{Ready}
Geometric slendernessReady\text{Ready}
Maximum centreline slopeReady\text{Ready}
End separationReady\text{Ready}
Bending strain energyReady\text{Ready}
Elastica arc closureReady\text{Ready}
Critical load from Southwell recordReady\text{Ready}
Acquired stationsReady\text{Ready}
Model stateReady\text{Ready}

Physics tutorial

Strength, crookedness and stability

BackgroundA shared axial loading frame connects physical geometry, a constitutive or stability model, and separately acquired observations.

Why it mattersUse loading, unloading and controlled geometry to distinguish competing explanations.

Start with the essentials

Focus question
Can strength alone prevent buckling?
One-sentence intuition
Follow the same physical state through apparatus, readouts and the energy or stability record.

Core mathematical model

Euler load

I=bh312Pcr=π2EIL2\begin{aligned}I&=\frac{bh^3}{12}\\P_{cr}&=\frac{\pi^2EI}{L^2}\end{aligned}

The two pinned ends select the first half-sine mode. Geometric slenderness and elastic stress must support this idealization.

Imperfection amplification

y0(s)=a0sin⁡πsLy(s)=y0(s)1−P/Pcr\begin{aligned}y_0(s)&=a_0\sin\frac{\pi s}{L}\\y(s)&=\frac{y_0(s)}{1-P/P_{cr}}\end{aligned}

This is a linear small-slope solution below the critical load, not a post-buckling trajectory.

Eccentric load

ye(s)=e[cos⁡ ⁣(P/EI(s−L/2))cos⁡ ⁣(P/EIL/2)−1]y_e(s)=e\left[\frac{\cos\!\left(\sqrt{P/EI}(s-L/2)\right)}{\cos\!\left(\sqrt{P/EI}L/2\right)}-1\right]

Equal eccentric end forces create end moments. The secant contribution superposes with the sine imperfection.

Perfect elastica

P=4EI K(k)2L2ΔL=2(1−E(k)K(k))\begin{aligned}P&=\frac{4EI\,K(k)^2}{L^2}\\\frac{\Delta}{L}&=2\left(1-\frac{\mathcal E(k)}{K(k)}\right)\end{aligned}

First pinned inextensible branch, parameterized by prescribed end shortening. Complete elliptic integrals define its load and geometry.

Southwell inference

v=y−y0vP=v+a0sin⁡(πsp/L)Pcr\begin{aligned}v&=y-y_0\\\frac{v}{P}&=\frac{v+a_0\sin(\pi s_p/L)}{P_{cr}}\end{aligned}

Fit a free offset and slope using raw additional displacement and force at one unchanged station; the reciprocal slope estimates the critical load.

Common difficulties

Model boundary

Typical misconceptionA smooth rendered curve proves physical validity.

Better mental modelUse explicit domain checks and acquired records; the teaching laws do not certify real specimens.

Run the experiment

  1. 01

    Amplify a tiny defect

    Increase compression with Small initial crookedness; inspect the side view.

    What to observe: The unloaded shape is grey; the loaded offset grows before the Euler load.
  2. 02

    Separate eccentricity

    Choose eccentric compression, then acquire a sweep.

    What to observe: An eccentric curve is measurable, but the sine-only Southwell estimate is withheld.
  3. 03

    Cross a model boundary

    Choose Beyond Euler load or a thicker, shorter column.

    What to observe: Acquisition stops rather than hiding a singularity, yield or stocky-column limit.
  4. 04

    Measure and compare branches

    Acquire a sine-defect sweep; then select shortening-controlled elastica and refine integration.

    What to observe: The raw regression estimates a critical force; the separate elastica branch closes its original arc length.