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Sandbox Physics

M042 · Energy and geometry

Roller-Coaster Energy Designer

Shape a circular or elliptical loop, release a sliding particle, and audit support, friction heat and finish speed. Acquire the physically valid trajectory and test a three-part design challenge.

Interactive modelRoller-Coaster Energy Designer
Selected station timeReady\text{Ready}
Selected speedReady\text{Ready}
Selected support over weightReady\text{Ready}
Peak support over weightReady\text{Ready}
Kinetic energyReady\text{Ready}
Potential energyReady\text{Ready}
Rail friction heatReady\text{Ready}
Energy closureReady\text{Ready}
Valid-prefix end timeReady\text{Ready}
Refinement time differenceReady\text{Ready}
Gravity from raw speed and heightReady\text{Ready}
Contact, load and finish challengeReady\text{Ready}
Contact stateReady\text{Ready}
Acquired stationsReady\text{Ready}

Physics tutorial

Energy, curvature and unilateral support

BackgroundA rail fixes geometry; gravity supplies energy, while support and travel time depend on the whole path.

Why it mattersUse the same model quantities for the apparatus, the physical motion and acquired observations.

Start with the essentials

Focus question
Can enough energy still lose contact?
One-sentence intuition
Follow the contact-valid prefix; never extend the constrained solution beyond detachment.

Core mathematical model

Geometry and support

t=drdsn=(−ty,tx)N/m=v2κ+g tx\begin{aligned}\mathbf t&=\frac{d\mathbf r}{ds}\\\mathbf n&=(-t_y,t_x)\\N/m&=v^2\kappa+g\,t_x\end{aligned}

The signed curvature and left normal use the actual designed centreline. Positive support pushes toward the left normal.

Tangential dynamics

d(v2)ds=−2gdyds−2μNmdQds=μN\begin{aligned}\frac{d(v^2)}{ds}&=-2g\frac{dy}{ds}-2\mu\frac{N}{m}\\\frac{dQ}{ds}&=\mu N\end{aligned}

Only positive support supplies kinetic friction. Squared speed and heat are integrated independently.

Energy ledger

12mv2+mgy+Q=12mv02+mgH\frac12mv^2+mgy+Q=\frac12mv_0^2+mgH

Normal support does no work while contact holds. The separately integrated heat closes the ledger.

Circular loop threshold

Ntop/m=vtop2/R−gvbottom2≥5gR\begin{aligned}N_{top}/m&=v_{top}^2/R-g\\v_{bottom}^2&\ge5gR\end{aligned}

For a frictionless circular loop, the contact condition is stronger than the energy needed merely to reach its top.

Raw-data gravity estimate

vi2=α−2g yiv_i^2=\alpha-2g\,y_i

Fit a free intercept and slope to acquired height and speed. Friction invalidates this inference and disables it.

Common difficulties

Idealized apparatus

Typical misconceptionA rendered ball includes rolling, suspension and real hardware dynamics.

Better mental modelThis is a sliding point-particle model. Rail and marker thickness are schematic.

Run the experiment

  1. 01

    Separate energy and contact

    Compare Complete circular loop, Ideal contact threshold and Energy without contact.

    What to observe: The valid blue prefix ends where the track can no longer push.
  2. 02

    Design the loop

    Change both loop radii, friction, load limit and required finish speed.

    What to observe: Meeting the energy budget alone does not pass the three-part challenge.
  3. 03

    Acquire a physical prefix

    Acquire the trajectory, open raw readings, then export CSV.

    What to observe: No sensor records are fabricated after contact loss or stall.
  4. 04

    Audit numerical agreement

    Double the intervals and compare the time refinement difference and independent heat ledger.

    What to observe: The difference is a refinement diagnostic, not a rigorous error bound.