A resonator chain transmits a finite frequency band
Represent a waveguide by resonators spaced by , with nearest-neighbour hopping . Set their common frequency to zero. A plane wave accumulates phase between neighbouring sites. Substitution into the discrete propagation equation gives a finite band.
No extended chain mode has a frequency outside . The slope of frequency against wave number is group velocity, the velocity of a narrow wavepacket centre. It is largest at band centre and vanishes at the edges. A broad pulse contains different velocities and changes shape.
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Why light can remain beside an atom in a gap
Outside the propagating band, an atom–chain eigenstate can carry a photon tail that decays away from the atom. That tail cannot carry all its probability to infinity as a propagating wave. This localized mixture of atom and light is a bound state.
Write for physical energy divided by the reduced Planck constant, with the same inverse-time units as . Outside the band, let the distant amplitude fall as . Substituting it into the source-free chain equation gives the relation below. Localization requires . The atomic coupling selects energies that also satisfy the central matching condition.
A bare excited atom is usually a superposition of extended and bound eigenstates. The extended contribution leaves; the bound contribution stays nearby. Atomic population alone measures only one component. A finite spatial window can also contain travelling light that has not yet left.
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Two coupling points turn a distance into a delay
A giant atom connects the same quantum system to two separated points. Light emitted at one point can reach the other and drive the same atom again. This path survives when the ends of the waveguide are moved arbitrarily far away.
Near band centre, take separation and units . Group velocity is two, giving a first travel-time estimate of . This estimate describes narrow band-centre components. Finite bandwidth spreads the return in time, so every small peak cannot be assigned the same exact delay.
Changing the coupling-point separation changes this return time and its phase. Moving only a distant endpoint should not change the first traversal between coupling points. That gives a useful numerical diagnostic.
Two return paths have different lengths
- Between two connections
- To the endpoint and back
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How a boundary reflection can mimic memory
An atom a distance from a hard boundary receives reflected light after roughly . Lengthening the chain moves that echo later. The existing single-excitation model has 401 sites, about 200 spacings from centre to endpoint. With , the fastest round-trip estimate is about 200 time units.
Its default run ends at time 64, before the main wavefront completes that trip. A lattice has small propagation tails, so endpoint population is still checked. A clean absorbing boundary requires a reflection check alongside its norm loss.
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Diagnose a returning pulse
Worked example: an atom population rises again near time sixteen. Lengthening the chain by half leaves this time nearly unchanged; halving the separation of the coupling points advances it. That supports propagation between the coupling points. A stationary cloud outside the band instead calls for a bound-state projection analysis.
Bandwidth determines environmental correlation times. A second coupling point or mirror supplies a particular return path. A finite endpoint may add an unintended echo. A model can contain all three, so identify their contributions before asking which returning field can be collected.