Start with the planet’s sideways motion
Use a planet of negligible mass around a primary star. Its position and velocity are measured relative to that star, in a frame whose axes do not rotate. The specific angular momentum is their cross product: “specific” means per unit planet mass. It points perpendicular to the instantaneous orbit plane.
At periapsis the radial velocity vanishes, so the speed is entirely sideways. The angular-momentum size is the periapsis distance times that speed. Substitute this speed into the two-body orbital energy, then use the ellipse’s periapsis distance. Cancelling the common factor gives the angular-momentum identity below.
A circle has the largest angular momentum at a given semimajor axis. An ellipse with eccentricity eight-tenths has only six-tenths of that circular value. Its planet spends a long time far out, then sweeps rapidly through periapsis. The cross product keeps track of that sideways motion throughout the orbit.
Reading: Tremaine & Yavetz, Why do Earth satellites stay up?, arXiv:1309.5244v1
Keep the component along the outer orbit axis
Average over the fast motion of the planet and its circular outer companion. The outer orbit then behaves like an axisymmetric ring. Rotating the entire inner ellipse around that ring’s axis changes no averaged interaction energy. The associated angular-momentum component is conserved.
Normalize the angular momentum by that of a circular orbit with the same semimajor axis. Its length becomes the square root of one minus eccentricity squared. The mutual inclination is the angle between its direction and the fixed outer axis. Their projection is therefore a product of that length and the inclination cosine.
For the default initial eccentricity of 0.05 and mutual inclination of 65 degrees, the conserved projection is approximately 0.422090. If eccentricity later reaches 0.8, angular-momentum length is 0.6 and the inclination must fall to about 45.3 degrees. The outer star has twisted the orbit while reducing its angular-momentum size.
The same calculation sets a geometric ceiling. Angular-momentum length cannot be smaller than the magnitude of one of its components. That ceiling alone would allow eccentricity about 0.907. The gravitational Hamiltonian imposes an additional restriction; the actual default averaged maximum is about 0.838909. The next chapter derives the stronger result.
Reading: Tremaine & Yavetz, Why do Earth satellites stay up?, arXiv:1309.5244v1 · Liu, Muñoz & Lai, Short-range forces in triple systems, arXiv:1409.6717v2
Stretching is different from dissipative migration
In this conservative averaged model the semimajor axis stays fixed. When eccentricity grows from 0.05 to 0.8, periapsis shrinks from 0.95 to 0.2 times the semimajor axis, while apoapsis expands from 1.05 to 1.8 times it. A close stellar passage is possible without the whole orbit becoming smaller.
To turn such passages into a short-period planet requires another process that removes orbital energy, usually tides in the migration scenario. A conservative relativistic periapsis precession rotates the ellipse but dissipates no energy. Neither a high eccentricity nor a precessing ellipse alone establishes that migration occurred.
The direct three-body problem also contains small changes in the osculating semimajor axis. That is an instantaneous Kepler description fitted to the current position and velocity, not the constant action of the averaged approximation. Keep these two meanings separate when reading the data plots.
Reading: Liu, Muñoz & Lai, Short-range forces in triple systems, arXiv:1409.6717v2 · Gupta et al., A hot-Jupiter progenitor on a super-eccentric retrograde orbit, Nature 632 (2024)
Estimate how long the torque takes
The companion’s differential acceleration scales with the inner orbit size divided by the cube of the outer separation. Its orbit-averaged potential per unit planet mass therefore has the scale below. Divide the circular angular momentum by that potential to obtain a characteristic secular time.
The adopted units set the gravitational constant, primary mass, companion mass and initial inner semimajor axis to one. The inner mean motion is then one, so its period is about 6.28 time units. With an outer separation of twelve, the companion-primary relative period is about 184.687 and the secular time is 1728. The saved default eccentricity cycle takes about five secular times.
The companion’s relative Kepler clock uses the sum of both stellar masses. The inner test particle’s clock uses the primary mass. Omitting that distinction changes the fast phase and the numerical comparison. Increasing outer separation slows the torque much more rapidly than it lengthens the outer period.
Averaging is most comfortable when both orbital periods are short compared with the change in orbital angular momentum. High eccentricity can make the angular momentum change sharply during one outer revolution, even when the semimajor axes look well separated. Saved trajectories will test how both hierarchy and angular-momentum changes affect this approximation.
Reading: Tremaine & Yavetz, Why do Earth satellites stay up?, arXiv:1309.5244v1 · REBOUND 5.2.2 official Kozai example and IAS15 integrator