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Sandbox Physics

B-X1 · Molecular energy from scattered light

Spontaneous Raman Spectrometer

Do molecular lines keep the same energy shift when the laser changes? Yes. A vibrational transition takes a fixed amount of photon energy, so changing the excitation moves the outgoing wavelength while preserving the Raman shift. Recovering it requires a calibrated spectral axis and enough resolution to separate nearby lines.

Calibrate a spectrometer, acquire weak scattered light and compare two excitation wavelengths. Separate a close pair of synthetic vibrational modes from fluorescence and counting noise.

Interactive modelSpontaneous Raman Spectrometer
Recorded photon counts—\text{—}
Measured Raman shift—\text{—}
Analysis—\text{—}

Recorded measurements

From photons to a Raman shift

Record a sample to view its measurement and analysis here.

Physical assumptions and sources

Two synthetic modes are broadened and integrated over physical wavelength-bin edges. A separate known reference estimates the wavelength offset. Background is estimated from edge bins, so broad backgrounds or unresolved overlap limit peak recovery. Intensities and widths are assumed; the model does not identify a real substance. Apparatus sizes and ray angles are schematic. Physical CCD columns show the selected counts with logarithmic brightness; moving light markers are path guides.

HORIBA · MacroRAM educational laboratory
NIST · spectral intensity calibration

Physics tutorial

Read a molecular energy difference

BackgroundA spectrograph records wavelengths. Molecular vibrations are compared by energy differences from the excitation light, so the laser wavelength belongs in the calibration.

Why it mattersA peak that moves when the laser changes can still represent the same vibration. Compare the stored spectra in wavelength and Raman-shift coordinates.

Start with the essentials

Focus question
Do molecular lines keep the same energy shift when the laser changes?
One-sentence intuition
A fixed vibrational energy gives a fixed reciprocal-wavelength difference, not a fixed wavelength difference.

Core mathematical model

Wavelength to Raman shift

Δν~=107(1λ0−1λs)  cm−1\Delta\widetilde\nu=10^7\left(\frac1{\lambda_0}-\frac1{\lambda_s}\right)\;\mathrm{cm}^{-1}

Both wavelengths are inserted in nanometres. Positive shift means the photon left energy in the sample.

Energy transferred to the vibration

ΔE=hc(100Δν~)\Delta E=hc(100\Delta\widetilde\nu)

The factor of one hundred converts inverse centimetres into inverse metres. The mode energy is held fixed when the excitation changes.

Independent photon counts

Ni∼Poisson⁡(μi),Var⁡Ni=μiN_i\sim\operatorname{Poisson}(\mu_i),\qquad\operatorname{Var}N_i=\mu_i

Each detector bin records its own signal and background photons. Subtracting an estimated background does not remove their counting noise.

Common difficulties

A smooth spectrum can hide two lines

Typical misconceptionEvery visible maximum is one molecular vibration, and smoothing can always recover a hidden pair.

Better mental modelFinite response blends nearby lines. The analysis requires two separated maxima with a resolved valley; otherwise it reports the pair as unresolved.

Run the experiment

  1. 01

    Calibrate before acquiring the sample

    Use Resolve the pair and Acquire calibration reference. Acquire the sample, then analyze stored samples.

    What to observe: The known reference estimates the wavelength offset. The sample analysis uses the stored counts and that frozen calibration.
  2. 02

    Change the laser

    Select Change excitation, calibrate the second laser, and acquire another sample. Switch the graph between wavelength and Raman shift.

    What to observe: The wavelength peaks move farther from the infrared source, but the recovered energy shifts agree within counting and calibration errors.
  3. 03

    Test resolution and background

    Acquire the Blurred doublet and Strong fluorescence presets.

    What to observe: Broadening can merge the pair. More background increases fluctuations even when its smooth trend is subtracted.
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