Skip to main content
Sandbox Physics

M065 · Normal modes

Coupled Oscillators

Can one bead's swing grow and fade while the energy in every normal mode stays fixed? It can. Written in normal modes, the chain splits into independent oscillators, and each one keeps its own energy forever. A single bead, though, moves with a mix of modes. When two of those modes have nearby frequencies, they drift in and out of step, and the bead's swing grows and fades: a beat.

Release a chain of beads and springs with fixed ends, either in one sine-shaped mode or in two neighboring high modes; the beads move along the chain. Pick any bead and compare the forces from its two springs with its acceleration, follow how each mode adds to its displacement, and track the energy computed directly from bead positions and velocities. The three-dimensional apparatus, the event cursor and the plots all show the same exact solution.

Interactive modelCoupled Oscillators
Exact normalized cursor00
Masses00
Excited modes00
First normalized angular frequency00
Second normalized angular frequency00
Coordinate-space energy00
Independent modal energy00
Signed coordinate minus modal energy00
Absolute beat-envelope period00
Inspected bead00
Inspected displacement00
Inspected velocity00
Force from left spring00
Force from right spring00
Inspected acceleration00

Physics tutorial

Coupled oscillators: find normal modes inside complex motion

BackgroundSprings link each mass to its neighbors. Certain shapes of the whole chain keep their form as they move, with every mass oscillating at the same frequency.

Why it mattersMolecular vibrations, phonons, vibrating structures and quantum fields all rely on the same idea: replace coupled coordinates with independent modes.

Start with the essentials

Focus question
Why can a chain of interacting masses still be split into as many independent simple motions as there are masses?
One-sentence intuition
In the right collective coordinates, a coupled system becomes a set of independent harmonic oscillators.

Core mathematical model

Discrete spring chain

mx¨j=k(xj+1−2xj+xj−1)m\ddot{x}_j=k(x_{j+1}-2x_j+x_{j-1})

Mass jj feels the sum of restoring forces from its two neighbors.

Fixed-end normal frequencies

ωp=2kmsin⁡ ⁣(pπ2(N+1))\omega_p=2\sqrt{\frac{k}{m}}\sin\!\left(\frac{p\pi}{2(N+1)}\right)

Each mode pp has its own frequency and fixed node pattern.

Common difficulties

A mode is not one mass

Typical misconceptionMode 2 means the motion of the second mass.

Better mental modelOne mode is a displacement pattern involving every mass.

Beats are not a new eigenfrequency

Typical misconceptionThe slow rise and fall of the amplitude means a new low-frequency mode has appeared.

Better mental modelThe beat is an envelope created by adding two nearby frequencies.

Run the experiment

  1. 01

    Find the lowest mode

    Choose Mode 1, press First-mode quarter period and look at each bead.

    What to observe: All masses move broadly in the same direction.
  2. 02

    Count nodes

    Compare Mode 2 with Mode 3.

    What to observe: Higher mode number adds internal nodes and raises frequency.
  3. 03

    Add two modes together

    Choose Neighboring-mode beats.

    What to observe: A slow envelope wraps the fast oscillation, yet the energy in each mode stays constant.
FeedbackSomething broken, confusing, or missing on this page?Tell us
What kind of feedback?

Sent with this page’s address, its Lab ID, the site language and your device type. Please leave out personal details. Feedback is kept for up to 12 months.Privacy policy