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Sandbox Physics

E52 · Photoelectron spectroscopy

UPS: Valence Bands & Work Function

Which two edges of a UPS spectrum give the work function? The secondary-electron cutoff at the low-energy end and the Fermi edge at the high-energy end. A negative sample bias moves both edges by the same amount, so their spacing stays fixed. Subtract that spacing from the photon energy and you have the work function. If the sample has no Fermi edge, take it from a metal reference in electrical contact with the sample.

Apply a negative bias, record a UV photoelectron spectrum and a separate metal reference, then place the fitting windows on the edges. Find the work function and the onset of the occupied band, and see what goes wrong with a missing Fermi edge, a cutoff the detector cannot reach, or too few counts.

Interactive modelUPS: Valence Bands & Work Function
Work function from measured edges—\text{—}
Fitted secondary-electron cutoff—\text{—}
Fitted Fermi reference—\text{—}
Measured cutoff-to-Fermi energy span—\text{—}
More measurements and target
Measured occupied-edge binding offset—\text{—}
Measured ionization energy—\text{—}
Instrument Gaussian-equivalent FWHM—\text{—}
Applied signed sample bias—\text{—}
Recorded sample counts—\text{—}
Independent reference counts—\text{—}
Fermi-zero source—\text{—}
Experiment target—\text{—}

Physics tutorial

Measure a span, not an absolute cutoff

BackgroundUV photons eject electrons from occupied states and also create slow secondary electrons. The Fermi edge and the secondary cutoff bound an energy span, and that span is set by the photon energy and the sample's work function.

Why it mattersThe low-energy cutoff can fall outside the range the analyzer accepts. The occupied band edge of a semiconductor can also be mistaken for the Fermi level.

Start with the essentials

Focus question
Which two edges of a UPS spectrum give the work function?
One-sentence intuition
A negative bias moves both edges up by the same energy, so their difference cancels the bias and the analyzer work function. When the sample has no Fermi edge, a separate metal reference supplies the Fermi zero.

Core mathematical model

Analyzer-side energies under negative sample bias

KF=hν−ϕa+e∣Vs∣Kc=ϕs−ϕa+e∣Vs∣\begin{gathered}K_F=h\nu-\phi_a+e|V_s|\\ K_c=\phi_s-\phi_a+e|V_s|\end{gathered}

Energies are measured in the analyzer vacuum. The sample and the reference share the applied bias, and the same bias offset appears in both the Fermi edge and the cutoff.

Work function from a measured span

ϕs=hν−(KF−Kc)\phi_s=h\nu-(K_F-K_c)

Taking the difference removes the analyzer work function and the bias. The He I photon energy is fixed at 21.218 eV. Both edges must lie inside the accepted energy range and be identified correctly.

Occupied-edge binding offset and ionization energy

EV=KF−KVI=ϕs+EV\begin{gathered}E_V=K_F-K_V\\ I=\phi_s+E_V\end{gathered}

The occupied edge of a semiconductor-like sample lies below the Fermi level. Its offset comes from the sample counts, measured from the separately recorded metal edge. In a metal this offset goes to zero.

Counts and the binding-energy scale

Di∼Poisson(μi),EB,i=KF,fit−KiD_i\sim\mathrm{Poisson}(\mu_i),\qquad E_{B,i}=K_{F,\mathrm{fit}}-K_i

The energy conversion reuses the acquired counts. Expected rates and display gain are kept apart from the measured spectra, and moving a fitting window does not record a new scan.

Gaussian stand-in for thermal broadening

ΔEF,thermal≃3.53kBT\Delta E_{F,\mathrm{thermal}}\simeq3.53k_BT

A Gaussian with the same FWHM as the derivative of the Fermi function shows thermal broadening. It does not reproduce the exact Fermi–Dirac line shape.

Common difficulties

The cutoff position alone is not enough

Typical misconceptionThe cutoff energy by itself is the sample's work function.

Better mental modelThe analyzer vacuum offset and the sample bias both shift the absolute cutoff. Measure the span from the Fermi edge to the cutoff instead.

The highest occupied edge is not always the Fermi level

Typical misconceptionAny edge at the high-energy end is the Fermi edge.

Better mental modelA semiconductor-like sample has an offset between its occupied band and the Fermi level. Treating that band edge as the Fermi edge overestimates the work function by the offset.

A valence spectrum is not the density of states

Typical misconceptionThe valence curve on screen is the exact density of states.

Better mental modelPhotoemission weighting and the instrument response both shape the intensity. This Lab uses invented valence peaks and does not invert for the density of states.

Run the experiment

  1. 01

    Bring the cutoff into view

    Start with no bias, then choose Measure a metal.

    What to observe: Negative bias lifts the sample cutoff above the 1 eV detector threshold, and both edges move together.
  2. 02

    Place the fitting windows

    Move the cutoff and Fermi fitting windows over the measured edges you can see, then compare with Wrong cutoff window.

    What to observe: A fitted edge needs enough counts and data on both sides. A smooth continuum is not accepted as a cutoff.
  3. 03

    Tell the Fermi edge from the band edge

    Choose Occupied edge below Fermi, then turn off Use the independent metal Fermi reference.

    What to observe: The sample has no Fermi edge of its own. Turning the separate reference back on recovers the work function and the ionization energy.
  4. 04

    Meet the target, then push it

    Use enough counts and a narrow instrument response, then press Check target. Change the bias and move the windows to follow the edges.

    What to observe: The edges move, but the recovered work function stays close to the separately known value.
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