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Sandbox Physics

E17 · Thin-foil orientation mapping

TKD: Through the Nanocrystal

Can a thinner specimen resolve smaller grains? Yes. When the beam passes through a thin foil, it has little room to spread, so the diffraction pattern comes from a smaller region than in ordinary reflection EBSD. The price is a weaker pattern from a thinner foil, and the geometry still has to be calibrated.

Compare a reflection geometry with an off-axis transmission screen. Then trade off foil thickness, counts and binning to recover the orientation and phase of nanometre-sized grains.

Interactive modelTKD: Through the Nanocrystal
Indexed one-axis rotation—\text{—}
Indexed teaching phase—\text{—}
Accepted fraction of all pixels—\text{—}
Assumed footprint FWHM along tilt—\text{—}
More measurements and target
Selected stored pattern counts—\text{—}
Selected detector pixel counts—\text{—}
Best candidate correlation—\text{—}
Best versus runner-up score gap—\text{—}
Independent check of phase and angle inputs—\text{—}
Accepted-pixel mean angular error—\text{—}
Incident dose per scan pixel—\text{—}
Experiment target—\text{—}

Physics tutorial

TKD: Through the Nanocrystal

BackgroundIn transmission Kikuchi diffraction the beam passes through a thin foil, and diffracted electrons leave the far side toward an off-axis screen. A thinner foil narrows the beam footprint, which helps with nanometre grains, but it can also give too few counts.

Why it mattersThe task asks for a map you can trust: at least 90 percent of pixels indexed, the correct phase and a rotation within 2 degrees in at least 90 percent of all pixels, and a mean angular error within 2 degrees for the accepted pixels. In TKD the assumed footprint FWHM must also stay at or below 12 nm.

Start with the essentials

Focus question
Can a thinner specimen resolve smaller grains?
One-sentence intuition
An indexing result depends on calibrated geometry, enough counts and a suitable family of candidates.

Core mathematical model

Cone edges on the detector

dhkl=a/h2+k2+l2∣s^⋅n^hkl∣=sin⁡θB=λ/(2dhkl)\begin{aligned}d_{hkl}&=a/\sqrt{h^2+k^2+l^2}\\|\widehat{\mathbf s}\cdot\widehat{\mathbf n}_{hkl}|&=\sin\theta_B=\lambda/(2d_{hkl})\end{aligned}

Ray directions that meet this condition lie on two Bragg cones. The trace of the lattice plane midway between them is the band center line; band intensity is prescribed.

Count first, index second

μj=Iτe η Bj∑kBkc^=arg max⁡c  (N−N‾)⋅(Tc−T‾c)∥N−N‾∥ ∥Tc−T‾c∥\begin{aligned}\mu_j&=\frac{I\tau}{e}\,\eta\,\frac{B_j}{\sum_k B_k}\\\widehat c&=\underset{c}{\operatorname{arg\,max}}\;\frac{(\mathbf N-\overline N)\cdot(\mathbf T_c-\overline T_c)}{\|\mathbf N-\overline N\|\,\|\mathbf T_c-\overline T_c\|}\end{aligned}

Each scan point stores one detector pattern. Indexing compares those counts with every entry in the stated dictionary of orientations and phases and keeps the highest normalized correlation.

Assumed foil response

p=t(1 nm)cos⁡ασ=(1 nm)4+(0.065p)2f=1−e−p/15η=0.08fe−p/150\begin{aligned}p&=\frac{t}{(1\,{\rm nm})\cos\alpha}\\\sigma&=(1\,{\rm nm})\sqrt{4+(0.065p)^2}\\f&=1-e^{-p/15}\\\eta&=0.08f e^{-p/150}\end{aligned}

Tilting the foil turns its normal thickness into a longer path along the beam. A narrower footprint can still deliver too few counts. The coefficients are teaching assumptions.

Common difficulties

Map color is not a full orientation

Typical misconceptionA beam IPF map alone proves every orientation and phase.

Better mental modelThe search covers only the stated one-axis family and the fictional phases. Treat dark pixels and narrow margins between candidates as limits of the result, and look at the stored patterns.

Run the experiment

  1. 01

    Predict before indexing

    Select a stored pixel and inspect its detector pattern. Compare it with the separately labeled input.

    What to observe: Band positions encode orientation; band widths also depend on the lattice spacing.
  2. 02

    Calibrate and search

    Try the wrong-center preset, then set the center error to zero. Sweep binning without reacquiring.

    What to observe: A wrong geometry can reject a clean pattern, and coarse binning wipes out the difference in band widths.
  3. 03

    Read the maps

    Compare beam IPF, phases, connected grains and neighbor disorientation. Select a boundary pixel.

    What to observe: Unindexed pixels stay dark, and grains are segmented from the recovered data only.
  4. 04

    Test the tradeoff

    Compare the same nanograin specimen in reflection and transmission. Sweep foil thickness and exposure.

    What to observe: A thin foil narrows the assumed footprint, but low counts or a thick foil can still make indexing fail.
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