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Optics 016 · How hot can sunlight make a tube

Solar Concentrator & Étendue

Why can’t any lens or mirror concentrate sunlight onto an arbitrarily small spot? Because no passive optical system can shrink étendue, the beam's area multiplied by its spread of directions. Squeeze the light onto a smaller spot and it must arrive from a wider range of angles, and the angles eventually run out. The highest possible concentration is set by the refractive index and the acceptance angle, with different limits for trough-shaped and dish-shaped concentrators.

Aim a parabolic trough or a still CPC at the sun, shrink the absorber, and see why concentration stops at a limit set by the sun’s size.

Interactive modelSolar Concentrator & Étendue
Aperture width over absorber size—\text{—}
Share of the sunlight reaching the absorber—\text{—}
Concentration delivered, against the limit for this light—\text{—}
Absorber temperature with no heat taken away—\text{—}
Average reflections before reaching the absorber—\text{—}
Focal length and tube diameter, or CPC height and absorber width—\text{—}
Share of all the absorber could take in that the sunlight fills—\text{—}
Limit for a dish that concentrates in both directions—\text{—}
Rays traced for this record—\text{—}

Physics tutorial

Concentrate sunlight and find where it stops

BackgroundA solar thermal plant heats a fluid with concentrated sunlight. A curved mirror gathers the light falling on a wide opening, the aperture, onto a much smaller absorber, a black tube or plate. The concentration says how many times brighter the light on the absorber is than sunlight falling straight on a plate.

Why it mattersThe hotter the absorber gets, the better a heat engine runs on it, so designers want to squeeze the light onto as small an absorber as they can. The sun is not a point, though: seen from Earth its disc is 0.53° across, and that width decides how far the light can be squeezed.

Start with the essentials

Focus question
The LS-2 trough gathers sunlight across 5 m onto a 70 mm tube, 22.7 times concentrated. Why can no mirror of any shape push sunlight in a trough past 215 times, and what does a thinner tube actually buy?
One-sentence intuition
Light entering an aperture of width WW from within ±δ\pm\delta of the sun’s centre has an étendue, its width times its spread of directions, of 2Wsin⁡δ2W\sin\delta. Mirrors can trade width for spread but can never shrink the product. An absorber of size AA takes in light from at most every direction above it, an étendue of 2A2A, so C=W/A≤1/sin⁡δC=W/A\le1/\sin\delta, 215 for the sun. A tube smaller than the sun’s image simply misses the light from the sun’s edges. A dish at its own limit makes every point of the absorber see the sun in every direction, and the absorber reaches the sun’s temperature; it cannot get hotter.

Core mathematical model

The étendue limit

2Wsin⁡δ≤2AC=WA≤1sin⁡δ≈215Cdish≤1sin⁡2δ≈46 200\begin{gathered}2W\sin\delta\le2A\\C=\frac{W}{A}\le\frac{1}{\sin\delta}\approx215\\C_{\mathrm{dish}}\le\frac{1}{\sin^{2}\delta}\approx46\,200\end{gathered}

Sunlight through the aperture WW spreads over ±δ\pm\delta; the absorber AA can accept at most every direction on its side, ±90∘\pm90^{\circ}. Mirrors keep the light’s étendue fixed and the absorber can take in no more than its own, which gives the limit 1/sin⁡δ1/\sin\delta in two dimensions. A dish, focusing in both directions, gets 1/sin⁡2δ1/\sin^{2}\delta (Rabl 1975, Eqs. II-14 and II-15).

The sun’s size

sin⁡δ=R⊙1 au,δ=0.266∘E⊙=σT⊙4sin⁡2δ=1361 W/m2\begin{gathered}\sin\delta=\frac{R_{\odot}}{1\,\mathrm{au}},\qquad\delta=0.266^{\circ}\\E_{\odot}=\sigma T_{\odot}^{4}\sin^{2}\delta=1361\,\mathrm{W/m^{2}}\end{gathered}

The IAU’s 2015 nominal solar radius, 695 700 km, seen from 1 au gives the sun’s angular radius δ\delta. A black surface facing a sun of effective temperature T⊙=5772 KT_{\odot}=5772\,\mathrm{K} receives the irradiance E⊙E_{\odot}, which matches the IAU’s nominal 1361 W/m21361\,\mathrm{W/m^{2}}: the disc’s size and its brightness agree.

A trough with a tube

d=2rsin⁡δ,W=2rsin⁡ϕC=Wπd=sin⁡ϕπsin⁡δ\begin{gathered}d=2r\sin\delta,\qquad W=2r\sin\phi\\C=\frac{W}{\pi d}=\frac{\sin\phi}{\pi\sin\delta}\end{gathered}

The mirror’s rim, at distance rr from the focus and rim angle ϕ\phi, makes the largest image of the sun, so the tube must be at least dd across to catch it. A tube absorbs, and loses heat, over its whole circumference πd\pi d, so the concentration is aperture over circumference. It peaks at ϕ=90∘\phi=90^{\circ} at 1/(πsin⁡δ)=68.41/(\pi\sin\delta)=68.4 (Rabl 1975, Eq. VI-1).

A compound parabolic concentrator

C=W2a′=1sin⁡θaL=(W2+a′)cot⁡θa\begin{gathered}C=\frac{W}{2a'}=\frac{1}{\sin\theta_{\mathrm{a}}}\\L=\left(\frac{W}{2}+a'\right)\cot\theta_{\mathrm{a}}\end{gathered}

Each wall is a piece of a parabola whose focus is the opposite end of the flat absorber 2a′2a' and whose axis is tilted by the acceptance half-angle θa\theta_{\mathrm{a}}. Every ray entering within ±θa\pm\theta_{\mathrm{a}} reaches the absorber and every other ray goes back out, so the CPC reaches the limit for that acceptance. Its height LL and wall length match Rabl’s Table II.

How hot the absorber gets

T=T⊙(Csin⁡2δ)1/4T=T_{\odot}\left(C\sin^{2}\delta\right)^{1/4}

A black absorber that loses heat only by radiating warms until it radiates σT4\sigma T^{4} as fast as it absorbs CE⊙C E_{\odot}. This stagnation temperature is 394 K for a bare plate facing the sun, 860 K for the LS-2 and 1507 K at the trough limit. At the dish limit, Csin⁡2δ=1C\sin^{2}\delta=1, it reaches the sun’s own 5772 K (Rabl 1975, Eq. II-23).

Common difficulties

A bigger mirror does not make a hotter spot

Typical misconceptionA large enough mirror could make its focus hotter than the sun.

Better mental modelThe sun’s angular size caps the concentration, whatever the mirror’s size. At the dish limit the absorber sees the sun in every direction and reaches 5772 K, the sun’s temperature. If it got hotter, heat would be flowing on its own from the cooler sun to the hotter absorber, which the second law forbids.

Aperture over absorber is not the concentration

Typical misconceptionDividing the aperture by the absorber size gives the concentration.

Better mental modelOnly when all the light lands. The 16.9 mm tube has a ratio of 94.2 but catches 87 % of the light, so it delivers 81.8.

A tube cannot reach the limit

Typical misconceptionA perfect parabolic trough reaches the étendue limit.

Better mental modelA trough focusing onto a tube reaches at most 1/π1/\pi of it, 68.4 against 215, because each point of the tube sees the sun in only a narrow band of directions. Reaching the limit takes a non-imaging design such as a CPC, which at ±30∘\pm30^{\circ} gives exactly 2.00, the limit for that acceptance.

Run the experiment

  1. 01

    Watch the light reach the tube

    Keep the default preset, LS-2 trough on target: all the light caught.

    What to observe: Every drawn ray lands on the 70 mm tube. Aperture over absorber, 5 m/(π⋅70 mm)5\,\mathrm{m}/(\pi\cdot70\,\mathrm{mm}), is 22.7, and all the sunlight arrives, so 22.7 is also the concentration delivered, against the 215 the sun allows. With no heat taken away the tube would reach 860 K.
  2. 02

    Let the tracking slip

    Drag the sun sideways, or load Tracking slips: light misses the tube.

    What to observe: Nothing is lost until the sun is about 0.5° off the axis. At 0.75°, 15 % of the light passes beside the tube, drawn in grey, and the concentration falls to 19.4. At 1° only 42 % arrives. The acceptance curve in the data row shows the drop.
  3. 03

    Shrink the tube

    Load Thinner tube: hotter, but light is lost, or lower the acceptance half-angle.

    What to observe: A 16.9 mm tube catches only 87 % of the light but concentrates what it catches 81.8 times, so it would reach 1184 K; aperture over absorber says 94.2. Shrinking it to 14.1 mm loses more light and gains nothing: in the sweep chart the delivered curve flattens near 82, 38 % of the limit, while aperture over absorber keeps rising.
  4. 04

    Open the rim to 90°

    Load The best a trough can do.

    What to observe: A 90° rim with a 23.3 mm tube, just wide enough for the sun’s image from the rim, catches all the light and delivers 68.4, which is 215/π215/\pi. In the map of directions each point of the tube sees the sun in only a narrow band; the band fills 32 % of the map, so the trough uses only that share of what the tube could take in.
  5. 05

    Stop tracking

    Load A still CPC catches the sun 20° off.

    What to observe: The CPC accepting ±30∘\pm30^{\circ} catches all the light from a sun 20° off its axis, after 0.72 reflections on average, and delivers 1.88; with the sun on its axis it delivers 2.00, the limit for light spread over ±30∘\pm30^{\circ}. Half a degree past 30° it catches nothing. It gives up most of the 215 so that it can sit still while the sun moves, and reaches only 461 K.
  6. 06

    Blur the sun

    Return to the default and raise the angular radius of the light to 1°.

    What to observe: Light spread over 1°, as from a mirror with a slight figure error, sets a limit of 57.3 instead of 215. The 70 mm tube now catches 93 % and delivers 21.2. At 3° the limit is 19.1 and the tube catches a third of the light.

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