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Sandbox Physics

Q022 · Avoided crossing / interference

Landau–Zener Passage

Does a slow sweep through an avoided crossing switch a two-level system into its other state? Yes, if the sweep is slow enough. The state stays on the lower energy branch, and across the avoided crossing that branch turns from one basis state into the other. A fast sweep leaves the state where it started. A second crossing shows interference.

Sweep a two-level system through an avoided crossing, compare its state in the energy basis and the fixed basis, then sweep back. Change the waiting time between the two passes, and the same finite-time evolution produces interference. Measure many freshly prepared trials and compare the counts with the model.

Interactive modelLandau–Zener Passage
Model final upper-energy probability—\text{—}
Total protocol time—\text{—}
Recorded evidence and model limits

Simulated independent trials

Count how often the state ends in the upper level

Blue dots and their pointwise 95% Wilson intervals come from the recorded trials. The gray curve is the finite-time model. The intervals are not simultaneous bands and carry no guarantee under optional stopping. Preview and replay never add trials.

Current setting: fraction / 95% range

—\text{—}

Infinite-sweep reference, when applicable

—\text{—}

Evolution steps / recorded trials

—\text{—}

Finite endpoints, the choice of initial state and dephasing can each make the infinite-sweep reference invalid. The return protocol is evolved in full, including the hold. The detector always measures in the final energy basis, even when the preview shows the fixed basis.

All measured settings
Latest 12 outcomes; CSV retains every trial and the preparation settings.

Physics tutorial

Following an avoided crossing

BackgroundWithout coupling, two energy levels would cross as the detuning changes. Coupling opens a gap between them. During the sweep the energy eigenstates rotate, but the fixed measurement basis stays the same.

Why it mattersSweep speed is the control. A slow sweep lets the state follow one energy level. A faster sweep splits it into two coherent parts, and a return pass recombines them.

Start with the essentials

Focus question
Does remaining in the lower energy state mean remaining in the same fixed-basis state?
One-sentence intuition
A state that follows its energy level adiabatically can swap its fixed-basis character. A second crossing reads out the relative phase built up between the two crossings.

Core mathematical model

Hamiltonian and units

HE0=Δσx+ϵ(τ)σz2,τ=E0t/ℏ\frac{H}{E_0}=\frac{\Delta\sigma_x+\epsilon(\tau)\sigma_z}{2},\qquad \tau=E_0t/\hbar

Energies are shown in units of the chosen energy scale, and times in units of the matching inverse angular frequency. The fixed zero state has the positive Pauli-z eigenvalue. This equation fixes the signs of the coupling and the detuning.

Energy states and finite sweep

E±/E0=±12Δ2+ϵ2,ϵ(τ)=−A+vτE_\pm/E_0=\pm\tfrac12\sqrt{\Delta^2+\epsilon^2},\qquad \epsilon(\tau)=-A+v\tau

The forward sweep ends at the positive endpoint detuning. In the return protocol the system waits there, then sweeps back at the same speed. The initial lower or upper energy state is defined at the actual finite starting point.

What the final detector measures

P+=1+r⋅nf2,P0=1+rz2P_+=\frac{1+\boldsymbol r\cdot\boldsymbol n_f}{2},\qquad P_0=\frac{1+r_z}{2}

The final detector projects onto the upper energy eigenstate. The blue fixed-zero population is a different observable. Neither curve is the path of a particle.

Reference for an infinitely long sweep

PLZ=exp⁡ ⁣(−πΔ22v)P_{\mathrm{LZ}}=\exp\!\left(-\frac{\pi\Delta^2}{2v}\right)

This formula assumes a linear sweep from minus infinity to plus infinity, a start in the lower energy state and no dephasing. The finite-time trajectories and the return fringes are not computed from it.

The dephasing model

ρ˙=−i[H/E0,ρ]+γ2(σzρσz−ρ)\dot\rho=-i[H/E_0,\rho]+\frac{\gamma}{2}(\sigma_z\rho\sigma_z-\rho)

Markovian pure dephasing acts in the fixed basis during the sweeps and the hold. Each numerical step applies an exact half step of dephasing, a midpoint unitary step, then another exact half step of dephasing. Relaxation, bath spectra and material calibration are not modeled.

From counts to a fraction

P^+(s)=n+(s)N(s)\widehat P_+(s)=\frac{n_+(s)}{N(s)}

Each outcome comes from a freshly prepared state that runs through the complete pulse at that scan setting. The Wilson interval at each point describes the Bernoulli uncertainty under this model; together the intervals do not form a joint band for the whole scan.

Common difficulties

Mixing up the two bases

Typical misconceptionIf the sweep is slow, the state does not change.

Better mental modelThe state stays in the same energy eigenstate, but that eigenstate changes its fixed-basis composition as the Hamiltonian changes.

Two crossings are not two coin flips

Typical misconceptionTwo passages are two independent coin flips, so their probabilities multiply.

Better mental modelThe two amplitudes stay coherent and keep their relative phase. The simulation carries that coherence through the whole protocol.

The formula is only a reference

Typical misconceptionThe exponential formula should match every finite pulse exactly.

Better mental modelThe formula assumes different endpoints, a particular initial state and no noise. The gray finite-time curve follows the evolution actually set up in the Lab.

Run the experiment

  1. 01

    Follow slowly

    Choose Slow passage and replay to the end. Inspect both population curves.

    What to observe: The upper-energy population stays small, yet the state swaps its fixed-basis character.
  2. 02

    Rush across

    Choose Fast passage, then collect a speed scan.

    What to observe: The faster the sweep, the more the state keeps its fixed-basis character, which leaves it in the upper energy state at the end.
  3. 03

    Return and interfere

    Choose Go there and back. Scan waiting time, then drag the waiting control.

    What to observe: The final counts oscillate with waiting time, because the phase built up before the second crossing changes.
  4. 04

    Check the limits

    Increase dephasing or move the endpoints inward, and repeat. Export the raw record.

    What to observe: The finite-time results can differ from the infinite-sweep formula, and noise changes the evolution itself.
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