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Sandbox Physics

M051 · Rotation / mass distribution

Moment-of-Inertia Designer

Build a balanced rotor from an annular carrier and two symmetric bead pairs. Drag the hollow release beads or the bearing, keep total mass fixed, then apply a calibrated torque. The inertia budget, angular speed and energy ledger update together; a faint curve compares a centered uniform disk of equal mass and radius.

Interactive modelMoment-of-Inertia Designer
Recorded time0 s0\,\mathrm{s}
Inertia about the bearing0 kg m20\,\mathrm{kg\,m^2}
Inertia about the mass center0 kg m20\,\mathrm{kg\,m^2}
Radius of gyration about bearing0 m0\,\mathrm{m}
Angular acceleration0 rad s−20\,\mathrm{rad\,s^{-2}}
Angular speed0 rad s−10\,\mathrm{rad\,s^{-1}}
Unwrapped rotation angle0 rad0\,\mathrm{rad}
Angular momentum about bearing0 kg m2 s−10\,\mathrm{kg\,m^2\,s^{-1}}
Rotational kinetic energy0 J0\,J
Applied couple work0 J0\,J
Work-energy balance defect0 J0\,J
Angular-impulse balance defect0 kg m2 s−10\,\mathrm{kg\,m^2\,s^{-1}}
Centered equal-mass disk reference0 kg m20\,\mathrm{kg\,m^2}
Centered equal-mass thin hoop reference0 kg m20\,\mathrm{kg\,m^2}

Physics tutorial

Distance from the axis is the design variable

BackgroundInertia weighs every element of mass by its squared perpendicular distance from the chosen rotation axis. A balanced layout can have many different inertias at the same total mass.

Why it mattersOpenStax University Physics sections 10.5, 10.7 and 10.8 connect distributed inertia, applied torque and rotational work. Here all three belong to the same editable apparatus.

Start with the essentials

Focus question
How can you change angular acceleration without changing total mass or torque?
One-sentence intuition
Specify the axis first. Moving a bead twice as far from that axis multiplies its contribution by four; moving the bearing adds the parallel-axis term.

Core mathematical model

Sum about the bearing

I=∫r⊥2 dm=ICM+Md2I=\int r_\perp^2\,\mathrm{d}m=I_{\mathrm{CM}}+Md^2

The balanced rotor has its mass center at the carrier center. The bearing offset is measured from that center.

Uniform annulus and bead pairs

ICM=M(1−f)2(R2+Rhole2)+Mf2(rx2+ry2)I_{\mathrm{CM}}=\frac{M(1-f)}2(R^2+R_{\mathrm{hole}}^2)+\frac{Mf}2(r_x^2+r_y^2)

The total bead mass is split equally across four beads. The supporting spokes carry no mass.

Constant applied couple

ω˙=τI,θ(t)=ω0t+τt22I\dot\omega=\frac\tau I,\qquad\theta(t)=\omega_0t+\frac{\tau t^2}{2I}

This trial changes angular speed while keeping the mass distribution and bearing fixed.

Independent balances

ΔK=τΔθ,ΔL=τt,K=12Iω2\Delta K=\tau\Delta\theta,\qquad\Delta L=\tau t,\qquad K=\frac12I\omega^2

Work and angular impulse use the same signed torque but different integrated motions.

Common difficulties

Same mass, different inertia

Typical misconceptionOnly the total mass determines rotational response.

Better mental modelCompare concentrated and rim layouts at the same torque. Their distance-weighted mass budgets differ.

The axis belongs in the specification

Typical misconceptionOne body has one universal inertia.

Better mental modelShift the bearing and inspect the added parallel-axis contribution.

Editing is a new release

Typical misconceptionDragging a bead while replaying conserves angular momentum.

Better mental modelLayout editing resets this rigid-body trial. Deforming a spinning body requires a separate internal-work model.

Run the experiment

  1. 01

    Design a fast response

    Concentrate the bead pairs and complete the torque trial.

    What to observe: Lower inertia produces larger angular acceleration.
  2. 02

    Compare a rim and a disk

    Use the rim preset and compare the disk reference curve.

    What to observe: The same total mass farther from the axis accelerates more slowly.
  3. 03

    Move the bearing

    Drag the red marker without changing mass or torque.

    What to observe: The inertia budget gains a parallel-axis term.
  4. 04

    Brake, then reverse

    Set positive initial spin and negative torque.

    What to observe: Motor work first removes energy and later adds it after reversal.