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Sandbox Physics

E28 · Crystal diffraction

Dynamical Diffraction: When Intensity Returns

Tilt a synthetic crystal, change its thickness and select a reflection. Compare counted bright-field and dark-field images with a two-beam prediction, then hide the specified defect contrast while retaining a strong reflection.

Interactive modelDynamical Diffraction: When Intensity Returns
Selected stored BF + DF counts—\text{—}
Recorded dark-field share—\text{—}
Model dark-field fraction—\text{—}
Selected local thickness—\text{—}
Dimensionless excitation departure—\text{—}
Model defect contribution to DF fraction—\text{—}
First-order kinematic intensity—\text{—}
Selected stored horizontal coordinate—\text{—}
Experiment target—\text{—}

Physics tutorial

Dynamical Diffraction: When Intensity Returns

BackgroundTilt a synthetic crystal, change its thickness and select a reflection. Compare counted bright-field and dark-field images with a two-beam prediction, then hide the specified defect contrast while retaining a strong reflection.

Why it mattersTarget: keep the specified defect present but set its reflection projection to zero. At the selected stored pixel obtain at least 1000 total counts, a model diffracted fraction of at least 0.75 and an absolute dimensionless departure at most 0.25.

Start with the essentials

Focus question
Does a thicker crystal always send more intensity into diffraction?
One-sentence intuition
A nonabsorbing crystal repeatedly exchanges intensity between transmitted and diffracted waves. Thickness fringes and bend contours can occur without compositional changes; absence of a modeled defect contribution does not prove absence of a defect.

Core mathematical model

Two-beam intensity

Ig=sin⁡2 ⁣(πt1+w2/ξg)1+w2I_g=\frac{\sin^2\!\left(\pi t\sqrt{1+w^2}/\xi_g\right)}{1+w^2}

The lossless solution exchanges intensity instead of increasing monotonically with thickness.

Departure and conservation

w=sgξg,I0+Ig=1w=s_g\xi_g,\qquad I_0+I_g=1

The conservation statement concerns expected intensities before independent counting noise.

Weak-scattering comparator

Ig(1)=(πtξg)2sinc⁡2(πtsg)I_g^{(1)}=\left(\frac{\pi t}{\xi_g}\right)^2\operatorname{sinc}^2(\pi t s_g)

Sinc means sine of the argument divided by the argument. Values above one signal a failed first-order approximation.

Common difficulties

Read the model boundary

Typical misconceptionA clean image or confident orientation removes the need to check the scattering model.

Better mental modelA nonabsorbing crystal repeatedly exchanges intensity between transmitted and diffracted waves. Thickness fringes and bend contours can occur without compositional changes; absence of a modeled defect contribution does not prove absence of a defect.

Run the experiment

  1. 01

    Predict the return

    Compare half and one extinction distance at exact Bragg orientation.

    What to observe: The thicker crystal returns intensity to the transmitted wave.
  2. 02

    Separate thickness from bending

    Use the contours preset, move the stored cursor and compare the known thickness reference.

    What to observe: Both thickness and excitation error change the same diffraction intensity.
  3. 03

    Hide contrast without removing the defect

    Compare visible and hidden presets, then reach the target. Switch apparatus channels without reacquiring data.

    What to observe: The defect remains a specimen input when its modeled contribution vanishes.