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E28 · Crystal diffraction

Dynamical Diffraction: When Intensity Returns

Does a thicker crystal always send more intensity into diffraction? No. Even in a crystal that absorbs nothing, intensity swings back and forth between the transmitted and diffracted beams as the thickness grows. As thickness or local tilt varies across the specimen, this exchange draws thickness fringes and bend contours, with no change in composition at all.

Tilt a synthetic crystal, change its thickness and choose a reflection. Compare the counted bright-field and dark-field images with the two-beam prediction, then make the contrast of the specified defect disappear while keeping a strong reflection.

Interactive modelDynamical Diffraction: When Intensity Returns
Selected stored BF + DF counts—\text{—}
Recorded dark-field share—\text{—}
Selected local thickness—\text{—}
Model defect contribution to DF fraction—\text{—}
More measurements and target
Model dark-field fraction—\text{—}
Dimensionless excitation departure—\text{—}
First-order kinematic intensity—\text{—}
Selected stored horizontal coordinate—\text{—}
Experiment target—\text{—}

Physics tutorial

Dynamical Diffraction: When Intensity Returns

BackgroundYou tilt a synthetic crystal, change its thickness and choose a reflection. You compare counted bright-field and dark-field images with the two-beam prediction, then make the contrast of the specified defect disappear while keeping a strong reflection.

Why it mattersThe goal is to keep the specified defect in the crystal while setting its reflection projection to zero. At the selected stored pixel you need at least 1000 total counts, a model diffracted fraction of at least 0.75 and a dimensionless departure no larger than 0.25 in magnitude.

Start with the essentials

Focus question
Does a thicker crystal always send more intensity into diffraction?
One-sentence intuition
In a crystal that absorbs nothing, intensity passes back and forth between the transmitted and diffracted waves as the thickness grows. Thickness fringes and bend contours can appear where the composition does not change at all. When the modeled defect contribution vanishes, that does not prove the defect is absent.

Core mathematical model

Diffracted intensity in the two-beam model

Ig=sin⁡2 ⁣(πt1+w2/ξg)1+w2I_g=\frac{\sin^2\!\left(\pi t\sqrt{1+w^2}/\xi_g\right)}{1+w^2}

Without absorption, the diffracted intensity rises and falls with thickness instead of growing steadily.

Dimensionless departure and intensity conservation

w=sgξg,I0+Ig=1w=s_g\xi_g,\qquad I_0+I_g=1

The two intensities add to one as expected values, before independent counting noise is added.

First-order weak-scattering approximation

Ig(1)=(πtξg)2sinc⁡2(πtsg)I_g^{(1)}=\left(\frac{\pi t}{\xi_g}\right)^2\operatorname{sinc}^2(\pi t s_g)

The sinc of an argument is its sine divided by the argument. A value above one means the first-order approximation has broken down.

Common difficulties

What the scattering model can show

Typical misconceptionIf the image looks clean and the orientation is known with confidence, there is no need to check the scattering model.

Better mental modelIn a crystal that absorbs nothing, intensity passes back and forth between the transmitted and diffracted waves as the thickness grows. Thickness fringes and bend contours can appear where the composition does not change at all. When the modeled defect contribution vanishes, that does not prove the defect is absent.

Run the experiment

  1. 01

    Predict when intensity returns

    At the exact Bragg orientation, compare a thickness of half an extinction distance with one full extinction distance.

    What to observe: In the thicker crystal, the intensity has gone back to the transmitted wave.
  2. 02

    Separate thickness from bending

    Load Bend contours and a thickness wedge, move the cursor over the stored image and compare it with the known thickness reference.

    What to observe: Thickness and excitation error both change the same diffracted intensity.
  3. 03

    Hide contrast without removing the defect

    Compare the visible and hidden defect presets, then reach the target. Switch the apparatus image between channels without acquiring new data.

    What to observe: The defect is still in the specimen even when its modeled contribution vanishes.
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