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Sandbox Physics

Driven Resonance & Phase Lag

Do a driven oscillator's largest swing and largest power intake happen at the same frequency? The power peak stays at the natural frequency. Damping shifts the displacement peak lower and can remove it.

Sweep a force-driven carriage through resonance. Compare its motion with the drive, measure amplitude and phase, and see where energy is absorbed.

Interactive modelDriven Resonance & Phase Lag
Acquired amplitudeLoading\text{Loading}
Acquired phase lagLoading\text{Loading}
Acquired mean powerLoading\text{Loading}
Model quality factorLoading\text{Loading}

Push at the right time

BackgroundA small periodic push can build a large vibration. Damping takes energy away, and the timing of the motion decides how much work each push does.

Why it mattersWatch the carriage and force arrow together. The largest motion and greatest energy transfer occur at different frequencies.

Focus question
Do displacement and absorbed power peak at the same frequency?
One-sentence intuition
At the natural frequency, velocity follows the force and absorbed power peaks. Damping shifts the displacement peak lower or removes it.

Core mathematical model

A force drives the mass

mx¨+cx˙+kx=F0sin⁡ωtm\ddot x+c\dot x+kx=F_0\sin\omega t

The mass moves horizontally. The force actuator pushes the mass directly; the spring anchor remains fixed.

Steady amplitude and lag

A=F0(k−mω2)2+(cω)2ϕ=atan2⁡(cω,k−mω2)\begin{gathered}A=\frac{F_0}{\sqrt{(k-m\omega^2)^2+(c\omega)^2}}\\\phi=\operatorname{atan2}(c\omega,k-m\omega^2)\end{gathered}

After the startup fades, motion follows the drive frequency. Lag is measured behind the applied sine force.

Average power and its bandwidth

P‾=12cω2A2Δf=c2πm,Q=mω0c\begin{gathered}\overline P=\tfrac12 c\omega^2 A^2\\\Delta f=\frac{c}{2\pi m},\qquad Q=\frac{m\omega_0}{c}\end{gathered}

These are exact steady results for linear viscous damping. Bandwidth is the half-maximum width of absorbed power.

The displacement peak shifts

ωpeak=ω01−2ζ2ζ<1/2\begin{gathered}\omega_{\rm peak}=\omega_0\sqrt{1-2\zeta^2}\\\zeta<1/\sqrt2\end{gathered}

At stronger damping there is no positive-frequency displacement peak. The power peak and a quarter-cycle displacement lag remain at the natural frequency.

Where drive work goes

E=12mx˙2+12kx2E−E0=W−Qheat\begin{gathered}E=\tfrac12 m\dot x^2+\tfrac12kx^2\\E-E_0=W-Q_{\rm heat}\end{gathered}

Work supplied and dashpot heat are integrated independently along the numerical trajectory.

Common difficulties

Two different peaks

Typical misconceptionThe mass must absorb the most power wherever displacement is largest.

Better mental modelPower depends on velocity and on when the force acts. Compare amplitude and mean power as damping grows.

Run the experiment

  1. 01

    Sweep through resonance

    Move Drive frequency ratio below and above one. Compare Build a resonance with Move against the push.

    What to observe: The motion grows near the peak and changes from following the force to moving nearly against it.
  2. 02

    Broaden the response

    Increase Damping ratio, then choose Record sweep.

    What to observe: The measured power peak broadens. Bandwidth and an estimated quality factor appear in the sweep diagnostics.
  3. 03

    Watch a startup

    Drag the gold carriage to prepare a release, or choose Startup.

    What to observe: The initial free motion fades into a response at the drive frequency.
  4. 04

    Keep the samples

    Choose Raw CSV and open Simulated observations and sweep results.

    What to observe: Each sweep point has its own sampled trajectory. Measurements and the steady reference can differ while a transient remains.
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