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Sandbox Physics

E38 · Electron imaging

DPC: Beam Deflection & Projected Fields

When does the shift of the diffraction disk measure the field in the specimen? Only when three things hold: the zero position is calibrated on a vacuum reference, the detector covers all the relevant angles, and scattering in the specimen doesn't reshape the disk. Even then, the shift measures only the total sideways push on the beam through the specimen. An electric or a magnetic field could give the same push, so one scan can't tell them apart.

Send a converging electron probe through a smooth junction and compare its diffraction disk with a separately recorded vacuum disk. Turn the measured center-of-mass shift into an electric-equivalent projected field, compare it with the quadrant-difference estimate, and see how clipping, counting noise and crystal scattering can imitate a field.

Interactive modelDPC: Beam Deflection & Projected Fields
Recovered electric-equivalent projection—\text{—}
Known-model RMS error—\text{—}
Minimum expected mask acceptance—\text{—}
Selected frame · accepted counts—\text{—}
More measurements and target
Recorded vacuum centroid—\text{—}
Known field-induced deflection—\text{—}
Known blurred source projection—\text{—}
Assumed force source—\text{—}
Incident specimen scan dose—\text{—}
Experiment target—\text{—}

Physics tutorial

Measure momentum before assigning a field

BackgroundAn electron that crosses a region with a smooth sideways force picks up sideways momentum, and its diffraction disk shifts. If the disk shifts without changing shape, a pixelated detector can measure the shift from the centroid of the recorded intensity.

Why it mattersThe apparent field also depends on where the detector zero lies, on angles the detector misses, on counting noise and on intensity the crystal scatters elsewhere.

Start with the essentials

Focus question
When does the shift of the diffraction disk measure the field in the specimen?
One-sentence intuition
The full center of mass and the quadrant difference estimate the shift in different ways, and the electric-equivalent projection reads as an electric field only once magnetic contributions and scattering are accounted for.

Core mathematical model

Depth turns a local field into a projection

E0=E0t,Δθx=−eE0tpv\mathcal E_0=E_0t,\qquad \Delta\theta_x=-\frac{eE_0t}{pv}

The local field is uniform through the chosen thickness. Without crystal coupling, doubling thickness doubles the expected impulse; it does not identify an unknown depth profile.

Lossless two-beam exchange

Pg(t)=κ2κ2+sg2sin⁡2 ⁣(πtκ2+sg2)P0(t)=1−Pg(t),κ=c80 nm\begin{aligned}P_g(t)&=\frac{\kappa^2}{\kappa^2+s_g^2}\sin^2\!\left(\pi t\sqrt{\kappa^2+s_g^2}\right)\\P_0(t)&=1-P_g(t),\qquad \kappa=\frac{c}{80\,\mathrm{nm}}\end{aligned}

The coupling c and excitation error determine reversible elastic transfer. A nonzero disk centroid can therefore occur with no electromagnetic field.

Relativistic Lorentz impulse on the electron

p Δθ=−e∫(E⊥v+z^×B⊥)dzp\,\Delta\boldsymbol\theta=-e\int\left(\frac{\boldsymbol E_\perp}{v}+\hat{\boldsymbol z}\times\boldsymbol B_\perp\right)\mathrm dz

The beam travels along positive z through the specimen. A positive projected electric field along x pushes the electron toward negative x, and a negative projected magnetic induction along y gives the same shift. The beam is fixed at 200 kV.

Centroid of the recorded pixels

θ‾x=∑m,nMmnDmnθx,m∑m,nMmnDmnΔθx=θ‾x,spec−θ‾x,vac\begin{gathered}\overline{\theta}_x=\frac{\sum_{m,n}M_{mn}D_{mn}\theta_{x,m}}{\sum_{m,n}M_{mn}D_{mn}}\\ \Delta\theta_x=\overline{\theta}_{x,\mathrm{spec}}-\overline{\theta}_{x,\mathrm{vac}}\end{gathered}

The separate vacuum frame uses the same angular mask. Every scan point shares this one reference, so its counting error appears at every point. Clipping can bias the specimen and vacuum centroids by different amounts.

Electric-equivalent projection

Ex,eq=−pveΔθx=∫Ex dz−v∫By dz\begin{aligned}\mathcal E_{x,\mathrm{eq}}&=-\frac{pv}{e}\Delta\theta_x\\&=\int E_x\,\mathrm dz-v\int B_y\,\mathrm dz\end{aligned}

Its unit is volts because it is a field integrated through the depth of the specimen, not the local field in volts per meter. The magnetic preset produces the same counts with no electric field at all.

Quadrant estimate for a small shift

Dx=NR−NLNR+NLΔθx≃πα4ΔDxΔDx=Dx,spec−Dx,vac\begin{aligned}D_x&=\frac{N_R-N_L}{N_R+N_L}\\\Delta\theta_x&\simeq\frac{\pi\alpha}{4}\Delta D_x\\\Delta D_x&=D_{x,\mathrm{spec}}-D_{x,\mathrm{vac}}\end{aligned}

This slope holds for a complete, uniform circular disk that moves only a little. Large offsets make the relation nonlinear, and an annular mask or a partly lost disk changes the calibration.

Electron count and specimen dose

Ne=Iτe,d=Ne(2 nm)2N_e=\frac{I\tau}{e},\qquad d=\frac{N_e}{(2\,\mathrm{nm})^2}

Each scan has 24 by 24 exposures at 2 nm spacing. The separate vacuum exposure adds acquisition time and data but no specimen dose. The error shown against the known model uses the probe-blurred projected field as its reference.

Common difficulties

Projection is not a local field

Typical misconceptionThe map gives a unique electric field at each atom.

Better mental modelThe map shows an electric-equivalent field integrated through the depth and averaged over the probe. Magnetic forces and scattering can contribute, and the Lab does no atomic multislice calculation.

A centered mask does not fix a shifted disk

Typical misconceptionA symmetric detector mask guarantees an unbiased centroid.

Better mental modelIf the shifted disk is cut differently from the vacuum disk, the symmetry of the mask does not restore the missing intensity.

Run the experiment

  1. 01

    Separate thickness and lattice impulse

    With crystal coupling off, drag the specimen from 100 to 50 nm and compare the recovered projection. Then choose No field · lattice impulse and vary thickness and mistilt.

    What to observe: The field contribution scales with path length. Elastic two-beam exchange varies non-monotonically and can create an apparent field even when the true field is zero.
  2. 02

    Predict the shift sign

    Compare the uncalibrated state with Calibrated center of mass.

    What to observe: Subtracting the measured vacuum counts removes the detector offset, but the noise in the reference stays.
  3. 03

    Cut off part of the disk

    Shrink the outer mask or exclude an inner region.

    What to observe: The centroid of a clipped disk no longer gives the average momentum of the whole beam. Missing counts can make both estimates invalid.
  4. 04

    Tell a measurement from its interpretation

    Compare the quadrant and scattering-artefact presets, then the magnetic preset.

    What to observe: The quadrant estimate drifts away from its small-shift calibration, and elastic dynamical diffraction creates false field contrast. Electric and magnetic sources can produce identical shift data.
  5. 05

    Meet the calibrated electric target

    Turn on vacuum correction, meet the stated limits on acceptance, counts, RMS error and dose, then check.

    What to observe: More exposure lowers counting noise, but it cannot remove the systematic bias from clipping or scattering.
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