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Sandbox Physics

Optics 058 · Diffraction, Fourier optics, and computational imaging

Crystal Diffraction & Reciprocal Space

Rotate a finite cubic crystal, compute its coherent detector record, explore Ewald intersections and white-beam Laue, then derive powder rings from the same pair distances. SC / BCC / FCC systematic absences expose what a diffraction pattern can and cannot reveal.

Interactive modelCrystal Diffraction & Reciprocal Space
Cell edge / selected plane spacing a,dhkla,d_{hkl}0.500.50
Selected basis intensity / atom count ∣F/nb∣2,Nat|F/n_b|^2,N_{\rm at}50%50\%
Ideal scattering angle / Ewald mismatch 2θB,ΔE2\theta_B,\Delta_E0.00π0.00\pi
Model regimevalid model regime\text{valid model regime}

Physics tutorial

Audit the physics of Crystal Diffraction & Reciprocal Space

BackgroundA diffraction spot is not a miniature atom or a painted reciprocal-grid point. It appears where the outgoing direction and wavelength make many scattered amplitudes agree: q=(sout−sin)/λ\mathbf q=(\mathbf s_{\rm out}-\mathbf s_{\rm in})/\lambda. The detector, cluster and Ewald geometry here use the same orientation and length scales.

Why it mattersHow can reciprocal-space spots and rings reveal an unknown real-space lattice?

Start with the essentials

Focus question
How can reciprocal-space spots and rings reveal an unknown real-space lattice?
One-sentence intuition
Add complex amplitudes from the actual finite cluster before squaring: I=∣∑je2πiq⋅rj∣2I=\left|\sum_j e^{2\pi i\mathbf q\cdot\mathbf r_j}\right|^2. A monochromatic exposure, white-beam Laue average and randomly oriented powder average are three different measurements, not interchangeable textures.

Core mathematical model

Cell edge is not plane spacing

ghkl=R (h,k,l)/adhkl=a/h2+k2+l22dhklsin⁡θB=λ\begin{aligned}\mathbf g_{hkl}&=R\,(h,k,l)/a\\d_{hkl}&=a/\sqrt{h^2+k^2+l^2}\\2d_{hkl}\sin\theta_B&=\lambda\end{aligned}

This Lab uses cubic conventional cells and reciprocal frequency in cycles per angstrom. The detector scattering angle is twice the Bragg plane angle. Changing the cell edge resizes all atomic coordinates, reciprocal spacing and the recorded pattern. Angles are derived from outgoing directions, not an independent spot animation.

One finite cluster, broadened peaks

J(q)=∣F(aRTq)∣2nb2∏α=13[sin⁡(πNtα)Nsin⁡(πtα)]2t=aRTq\begin{aligned}J(\mathbf q)&=\frac{|F(aR^{\mathsf T}\mathbf q)|^2}{n_b^2}\\&\quad\prod_{\alpha=1}^{3}\left[\frac{\sin(\pi N t_\alpha)}{N\sin(\pi t_\alpha)}\right]^2\\\mathbf t&=aR^{\mathsf T}\mathbf q\end{aligned}

The formula is the exact factorization of a cube of complete conventional cells, each with the same point-scatterer basis. At integer reciprocal coordinates the ratio is evaluated by its continuous limit. Increasing cell count narrows the peaks; off-node side lobes are real consequences of the finite cluster. The intensity normalization is by squared atom count, not a moving brightest pixel.

Basis interference creates systematic absences

FSC=1FBCC=1+(−1)h+k+lFFCC=1+(−1)h+k+(−1)h+l+(−1)k+l\begin{aligned}F_{\rm SC}&=1\\F_{\rm BCC}&=1+(-1)^{h+k+l}\\F_{\rm FCC}&=1+(-1)^{h+k}\\&\quad+(-1)^{h+l}+(-1)^{k+l}\end{aligned}

All atoms have equal unit scattering amplitude. BCC permits an even index sum; FCC permits all-even or all-odd indices. A hollow reciprocal node is a basis absence, distinct from an allowed reflection that happens to miss the Ewald sphere. A finite detector pixel away from a forbidden node may still contain side-lobe intensity.

Ewald sphere and white-beam Laue

∣sin/λ+g∣=1/λλg=−2sin⋅g∣g∣2J‾Laue=∫w(λ)Jλ dλ\begin{aligned}|\mathbf s_{\rm in}/\lambda+\mathbf g|&=1/\lambda\\\lambda_{\mathbf g}&=-\frac{2\mathbf s_{\rm in}\cdot\mathbf g}{|\mathbf g|^2}\\\overline J_{\rm Laue}&=\int w(\lambda)J_\lambda\,\mathrm d\lambda\end{aligned}

The incident direction is laboratory positive x; the Ewald centre is negative incident frequency, so the sphere passes through the reciprocal origin. A white beam supplies a nest of radii, not one monochromatic sphere with extra invented spots. Intensities from different wavelengths add incoherently. The uniform band average here uses 96–512 parameter-adaptive composite Simpson intervals and approaches the single-wavelength result at zero bandwidth.

Powder rings from pair distances, not painted circles

Jpowder(q)=1Nat2∑i,jsin⁡(2πqrij)2πqrijq=2sin⁡θλrdetector=Dtan⁡(2θ)\begin{aligned}J_{\rm powder}(q)&=\frac1{N_{\rm at}^2}\sum_{i,j}\frac{\sin(2\pi q r_{ij})}{2\pi q r_{ij}}\\q&=\frac{2\sin\theta}{\lambda}\\r_{\rm detector}&=D\tan(2\theta)\end{aligned}

The Debye sum is the exact isotropic orientation average of the same cluster. Equal pair distances are grouped exactly, including self-pairs. A radial table interpolates the detector values; the displayed profile then averages those detector records in annuli. Rotating one illustrative grain cannot alter an isotropic powder pattern. Gold ring positions are separate ideal Bragg references, not the calculated finite-cluster peaks.

What this record cannot prove

J=∣A∣2⇏arg⁡AJ=|A|^2\quad\not\Rightarrow\quad\arg A

Spot positions and systematic absences constrain a proposed lattice, but intensity alone does not uniquely recover atomic structure. This is a forward model with equal point scatterers, not experimental material identification. Form factors, polarization, absorption, dynamical scattering, temperature and detector noise are omitted. Exposure is a declared logarithmic display gain; the central beamstop does not rewrite raw scattering values.

Common difficulties

No spot does not imply no planes

Typical misconceptionEvery reciprocal point must appear on the detector; any missing spot means the crystal is wrong.

Better mental modelFirst check basis extinction, then elastic Ewald geometry, wavelength band and the finite forward detector. These are different reasons for a missing signal; none requires painting a spot.

Run the experiment

  1. 01

    Scene 1: Monochromatic rocking

    Start at the monochromatic preset. Rock yaw a few degrees; inspect the atom cluster, receiving face and reciprocal space separately.

    What to observe: A spot strengthens near an Ewald intersection and weakens away; increasing finite cell count narrows it.
  2. 02

    Scene 2: White-beam Laue

    Choose Laue. Narrow its bandwidth to zero and compare with monochromatic mode at identical settings; then rotate the crystal.

    What to observe: A band of wavelengths supplies more elastic solutions; shrinking the band returns the single-wavelength record.
  3. 03

    Scene 3: Powder and missing reflections

    Choose powder. Switch SC, BCC and FCC; select the first missing reflection, change cell edge, and rotate the illustrative grain.

    What to observe: Powder rings shift when cell edge or wavelength changes, but not when an illustrative grain rotates; basis absences distinguish the three candidate lattices.
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