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Sandbox Physics

E12 · Segmented SEM detection

BSE: Composition or Orientation?

Record both sides of a split detector. Calibrate their gains, switch between sum and difference, then rotate the specimen to separate material contrast, surface relief and prescribed channeling.

Interactive modelBSE: Composition or Orientation?
Stored left counts—\text{—}
Stored right counts—\text{—}
Count-derived material contrast—\text{—}
Separate unchanneled input contrast—\text{—}
Contrast error against input—\text{—}
Contrast to representative pixel noise—\text{—}
Selected count-derived asymmetry—\text{—}
Prescribed mean channeling suppression—\text{—}
Mean asymmetry error against geometry—\text{—}
Incident dose per pixel—\text{—}
Experiment target—\text{—}

Physics tutorial

BSE: Composition or Orientation?

BackgroundRecord both sides of a split detector. Calibrate their gains, switch between sum and difference, then rotate the specimen to separate material contrast, surface relief and prescribed channeling.

Why it mattersTarget: use the calibrated sum away from strong grain channeling. Material contrast error at most 0.03, asymmetry mean error at most 0.05, representative pixel CNR at least 8 and prescribed mean channeling suppression at most 3 percent.

Start with the essentials

Focus question
Can brighter grains prove a different composition?
One-sentence intuition
A brighter region can reflect material, orientation or collection geometry.

Core mathematical model

Count expectations

Ninc=Iτ/eμL=Nincηf(1−a)/2μR=gRNincηf(1+a)/2\begin{aligned}N_{inc}&=I\tau/e\\\mu_L&=N_{inc}\eta f(1-a)/2\\\mu_R&=g_RN_{inc}\eta f(1+a)/2\end{aligned}

The sector responses complement each other; gain is independent count sensitivity.

Process the same acquisition

Y^=NL+NR/gRNincfa^=NR/gR−NLNR/gR+NL\begin{aligned}\widehat Y&=\frac{N_L+N_R/g_R}{N_{inc}f}\\\widehat a&=\frac{N_R/g_R-N_L}{N_R/g_R+N_L}\end{aligned}

The sum retains material and orientation response; difference is a direction diagnostic.

Declared teaching response

η(Z)=0.04+0.45(1−e−Z/30)c(α,αg)=1−0.22e−(α−αg)218\begin{aligned}\eta(Z)&=0.04+0.45(1-e^{-Z/30})\\c(\alpha,\alpha_g)&=1-0.22e^{-\frac{(\alpha-\alpha_g)^2}{18}}\end{aligned}

Prescribed yield and rocking dip, not a calculated material cross section.

Common difficulties

Separate appearance from information

Typical misconceptionA clearer-looking image guarantees the right interpretation.

Better mental modelDisplay gain does not change counts or undo physical mixing. The input reference is separate from measurement.

Run the experiment

  1. 01

    Predict the ambiguity

    Inspect the one-sided image and separate material and orientation inputs. Predict which stripes will change on rotation.

    What to observe: Brightness contains several physical responses at once.
  2. 02

    Calibrate before combining

    Use the uncalibrated preset, then apply known gain calibration. Compare the asymmetry audit.

    What to observe: Unequal sectors leak common response into their difference.
  3. 03

    Rotate the specimen

    Sweep rocking tilt through the two prescribed grain dips, then away from both.

    What to observe: The sum cancels symmetric relief but still sees orientation.
  4. 04

    Check the measurement

    Choose the sum, calibrate, avoid grain dips and use enough dwell to meet the target.

    What to observe: A composition claim needs controls and a noise budget.