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Sandbox Physics

M025 · Structural mechanics

Beam Bending Laboratory

Change supports and solid or hollow rectangular sections. Read shear, bending moment, curvature and fiber stress; infer Young modulus from acquired deflections.

Interactive modelBeam Bending Laboratory
Model domain—\text{—}
Left vertical reaction—\text{—}
Right vertical reaction—\text{—}
Largest displacement magnitude—\text{—}
Probe vertical displacement—\text{—}
Maximum axial stress magnitude—\text{—}
Largest ideal utilization—\text{—}
Elastic strain energy—\text{—}
Cross-section area—\text{—}
Section second moment—\text{—}
Actual displacement display gain—\text{—}
Acquired load stations—\text{—}
Modulus fitted from raw data—\text{—}
Fit residual RMS—\text{—}
Clamp holding moment—\text{—}
Moment at probe—\text{—}
Right-hand shear at probe—\text{—}
Curvature at probe—\text{—}
Upper fiber stress at probe—\text{—}
Lower fiber stress at probe—\text{—}
Length / section depth—\text{—}

Physics tutorial

A support changes the entire bending field

BackgroundThe structure is loaded slowly, so inertia is excluded.

Why it mattersMIT mechanics-of-materials notes derive joint equilibrium, axial elasticity and Euler–Bernoulli bending from a common force and energy budget.

Start with the essentials

Focus question
Can measured bending reveal material stiffness?
One-sentence intuition
Geometry fixes the load paths; cross-section and modulus fix compliance.

Core mathematical model

Moment and curvature

EI v′′(x)=M(x)EI\,v^{\prime\prime}(x)=M(x)

Upward displacement is positive. Positive sagging moment makes the upper fiber compressive and the lower fiber tensile.

Section and fiber stress

I=bh3−bihi312,σx=−MyII=\frac{bh^3-b_i h_i^3}{12},\qquad\sigma_x=-\frac{My}{I}

The inner rectangle vanishes for a solid section. Height follows the vertical direction; width follows depth.

Distributed load and point jump

M′=V,V′=−q,V(a+)−V(a−)=−PM^{\prime}=V,\quad V^{\prime}=-q,\quad V(a^+)-V(a^-)=-P

A downward point load gives a shear jump while moment, slope and displacement remain continuous.

Boundary conditions matter

v(0)=v(L)=0orv(0)=v′(0)=0v(0)=v(L)=0\quad\text{or}\quad v(0)=v^{\prime}(0)=0

The first pair is for a simply supported beam, the second for a left cantilever clamp. The free tip has zero moment and shear beyond applied tip loads.

Modulus from an acquired slope

vp=αP+β,E^=Cgeometryα^v_p=\alpha P+\beta,\qquad\widehat E=\frac{C_{\mathrm{geometry}}}{\widehat\alpha}

Fit the actual simulated raw deflections. Known geometry gives unit-modulus compliance; a free intercept absorbs the fixed distributed-load offset.

Common difficulties

Magnification is not deformation

Typical misconceptionThe visibly bent apparatus gives the physical displacement directly.

Better mental modelUse the readout or quantitative plot; the 3D gain changes only presentation.

Limits do not predict collapse

Typical misconceptionA rod or beam beyond an ideal limit still obeys this linear model.

Better mental modelTreat the red solution as extrapolation; plastic flow and post-buckling are omitted.

Raw data come first

Typical misconceptionThe fitted modulus simply repeats the reference slider.

Better mental modelClear observations: the estimate disappears. Acquire several loads and change noise to inspect inference quality.

Run the experiment

  1. 01

    Change the load path

    Compare simply supported and cantilever presets.

    What to observe: Reactions and internal forces change together.
  2. 02

    Move the load and probe

    Drag the two colored station handles below the apparatus.

    What to observe: The probe follows physical deflection; moving it clears incompatible measurements.
  3. 03

    Measure the material

    Acquire nine load steps, add bounded sensor noise and export raw readings.

    What to observe: Slope estimates modulus; residuals reveal sensor scatter.
  4. 04

    Audit the boundary

    Try a hollow section, then the short-beam warning.

    What to observe: A low stress does not remove a shear-deformation warning.